very simple, we use the formula sin(a+b)=sinacosb +
sinbcosa and sin(20)=2sinacosa
5pi = 2pi/3+3pi/3,
First, we use sin(a+b)=sinacosb + sinbcosa
sin(5pi/3)=sin(2pi/3+3pi/3)=
sin(2pi/3+pi)=
sin(2pi/3)cos(pi) +sin(pi)cos(2pi/3)
but we know that sin(pi)=
0, and cos (pi) = -1, so sin(5pi/3)=
- sin(2pi/3)
now, use sin(2a)=2sinacosa,
sin(5pi/3)= - sin(2pi/3)= -2sin(pi/3)cos(pi/3)
sin<span>(5pi/3)=
-2sin(pi/3)cos(pi/3)</span>
<span>sin(pi/3)= 0.86,
cos(pi/3)=0.5, finally we have </span>sin<span>(5pi/3)= -0.86 x 0.5= -0.43</span>
The answer is B as it is the only one that matches the 2 inequalities.
Answer:
D is the correct a
Step-by-step explanation:
From table A-3: Areas under the normal curve
we can deduce that k=0.9
Answer:
arc AM = 114°
Step-by-step explanation:
the measure of a tangent- chord angle is half the measure of its intercepted arc, that is
∠ MAC = 
(AM )
57° = AM ( multiply both sides by 2 to clear the fraction )
114° = AM
Answer:
![3x^{2}y^{2}\sqrt[4]{7xy^{3}}](https://tex.z-dn.net/?f=3x%5E%7B2%7Dy%5E%7B2%7D%5Csqrt%5B4%5D%7B7xy%5E%7B3%7D%7D)
.
Step-by-step explanation:
Since we have to find the simplified form of the expression as below
![\sqrt[4]{567x^{9}y^{11}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B567x%5E%7B9%7Dy%5E%7B11%7D%7D)
we will solve the expression as below
![=[567x^{9}y^{11}]^{\frac{1}{4}}](https://tex.z-dn.net/?f=%3D%5B567x%5E%7B9%7Dy%5E%7B11%7D%5D%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D)
![=3x^{2}y^{2}\sqrt[4]{7xy^{3}}](https://tex.z-dn.net/?f=%3D3x%5E%7B2%7Dy%5E%7B2%7D%5Csqrt%5B4%5D%7B7xy%5E%7B3%7D%7D)
.
