Preparation
• Grate a small red cabbage. If you do not want to grate the entire cabbage, grating half of a cabbage should be enough. Put the fine, pulpy grated cabbage into a large bowl or pot.
• Boil a pot of water. Use caution when handling the boiling water. Pour the boiling water into the bowl with the cabbage pulp until the water just covers the cabbage.
• Leave the cabbage mixture steeping, stirring occasionally, until the liquid is room temperature. This should take at least half an hour. The liquid will become red or purplish-red in color.
• Place a strainer over another large bowl or pot and pour the cabbage mixture through the strainer to remove the cabbage pulp. Press down on the pulp in the strainer, such as by using a large spoon, to squeeze more liquid out of the pulp.
• In the bowl, you should now have only liquid that will either be purple or blue in color. This will be your indicator solution, which you will use to test the pH of different liquids.
<span>• Children should wear goggles or other protective eyewear and adults should supervise and use caution when handling bleach and vinegar, because they can irritate eyes and skin.</span>
Let's make ;
A = ounces solution A
B = ounces solution B
total number of ounces:
A + B = 120
concentration:
0.65A + 0.80B = 0.7(120)
Substitute A for 120 - B in the second equation to combine them.
0.65(120 - B) + 0.80B = 84
78 - 0.65B + 0.80B = 84
0.15B = 84 - 78
0.15B = 6
B = 6/0.15
B = 40 ounces
Then... A = 120 - 40
A = 60 ounces
Answer: 24.13 g Cu
Explanation:
<u>Given for this question:</u>
M of CuO = 30 g
m of CuO = 79.5 g/mol
Number of moles of CuO = (given mass ÷ molar mass) = (30 ÷ 79.5) mol
= 0.38 mol
The max number of CuO (s) that can be produced by the reaction of excess methane can be solved with this reaction:
CuO(s) + CH4(l) ------> H2O(l) + Cu(s) + CO2(g)
The balanced equation can be obtained by placing coefficients as needed and making sure the number of atoms of each element on the reactant side is equal to the number of atoms of each element on the product side
4CuO(s) + CH4(l) ----> 2H2O(l) + 4Cu(s) + CO2(g)
From the stoichiometry of the balanced equation:
4 moles of CuO gives 4 moles of Cu
1 mole of CuO gives 1 mol of Cu
0.38 mol of CuO gives 0.38 mol of Cu
Therefore, the grams of Cu that can be produced = 0.38 × molar mass of Cu
= 0.38 × 63.5 g
= 24.13 grams
Therefore, 24.13 grams of copper could be produced by the reaction of 30.0 of copper oxide with excess methane
Answer:
1,2 dichlorobenzene was used as the solvent for the diels alder reaction: <em>because the co elimination part of the reaction needs high temp and a high boiling point solvent such as 1,2 dichlorobenzene</em>
Explanation:
Diels-Alder Reaction is a useful synthetic tool to prepare cyclohexane rings. It is a process, which occurs in a single step that consists of a cyclic redistribution of its electrons. The two reagents are bond together through a cyclic transition state in which the two new C-C bonds are formed at the same time. For this to occur, most of the time, it is necessary a high temperature and high-pressure conditions. Since 1,2 dichlorobenzene has a boiling point of 180ºC is a good solvent for this type of reactions.
Answer:
Okay so set up an equation for what's happening
_C + _H + _Cl + O2 --> _CO2 + _H2O
0.451g of CO2. Convert to moles by using the molar mass of CO2 which is 44 g/mol. Now look at the ratio between Carbon and Oxygen in CO2. It's 1C:2O You just want to find C.. so do the number of moles CO2 and multiply it by 1 since the ratio says 1 carbon atom. Now you have moles of carbon. Put this number aside for later.
Do the same thing with H2O. Convert to moles by using the molar mass of H2O which is 18 g/mol. Now look at the ratio between Hydrogen and Oxygen. It's 2H:1O You just want H.. so do the number of moles of H2O and multiply it by 2 since there's 2 hydrogen atoms. Now you have the moles of hydrogen & put this number aside for later
Lastly, you need to find the chlorine. uuhhh I cant figure this part out
Explanation: ..
I hope I helped lol!
