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Mice21 [21]
3 years ago
9

What is the percentage error of length measurement of 0.229cm if the correct value is 0.225cm

Chemistry
2 answers:
Mars2501 [29]3 years ago
5 0

Percent error is the difference between the measured and known value, divided by the known value, multiplied by 100%.

So first, we take our measured value, .299 cm, minus our known value, .225 cm.

.299 cm - .225 cm=.004 cm

Next, we divide that by our known value

\frac{.004}{.225}=.0177777778

Finally, multiply your answer by 100

.0177777778 x 100= 1.77777778 %

Round to three significant figures, and you're done.

=1.78 % error



My name is Ann [436]3 years ago
4 0

% error = 2 %

\% \text{error} = \frac{\text{0.225 cm} - \text{0.229 cm}}{\text{0.225 cm}} \times100 \% = \frac{|-0.004|}{0.225} \times 100 \% = 2 \%

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An organic compound has the empirical formula C2H4O. what is the compound?
rosijanka [135]

Answer:

The correct answer is - butanoic acid

Explanation:

An empirical formula is the general formula or base formula that is the simplest positive integer ratio of atoms present in a compound. The empirical formula is specific to specific compounds or types of compounds.

Among the given options, the empirical formula C2H4O is butanoic acid as the molecular formula of butanoic acid is - C4H8O2 which is multiple of C2H4O. Other compounds have different than this empirical formula.

3 0
3 years ago
Suppose the thermometer is miscalibrated to read .3c higher than actual. does this error in calibrations result in the molar mas
andrey2020 [161]
The answer to this question would be: too low

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5 0
3 years ago
BASED ON THE INFORMATION BELOW. CALCULATE THE MASS FOR ONE OF THESE ATOMS:
stepladder [879]

C = 12 g

O = 16 g

H = 1 g

<h3>Further explanation </h3>

Conservation of mass stated that  

<em>In a closed system, the masses before and after the reaction are the same </em>

we can calculate the mass of each atom in the compound :

O in O₂ :

mass O₂ = 32

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H in H₂O

mass H₂O = 18

mass 2.H + mass O = 18

mass 2.H + 16 = 18

mass 2.H=2

mass H = 1 g

C in CH₄

mass CH₄ = 16

mass C + mass 4.H = 16

mass C + 4.1=16

mass C = 12 g

or we can use formula :

Mass of a single C :

\tt =\dfrac{Ar~C}{MW~CO_2}\times mass~CO_2\\\\=\dfrac{12}{44}\times 44=12

7 0
3 years ago
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2. it becomes a liquid
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The change in state is due to the loss of energy.

3 0
3 years ago
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sesenic [268]

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Explanation:

6 0
2 years ago
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