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belka [17]
3 years ago
9

What is temperature?

Chemistry
2 answers:
Mashutka [201]3 years ago
7 0

Answer: temperature is a measure of the average kinetic energy of the particles in an object

Explanation:

Andrew [12]3 years ago
3 0

Answer:

Temperature is the degree of hotness or coldness of a place or a body. Heat Energy is the form of energy

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Water (10 kg/s) at 1 bar pressure and 50 C is pumped isothermally to 10 bar. What is the pump work? (Use the steam tables.) -7.3
Andreyy89

Answer:

The pump work is 3451 kJ/s

Explanation:

Pump work (W) is calculated as

W = (h_f - h_i) \times \dot{m}

where

h_f is the enthalpy of water at its final state

h_i is the enthalpy of water at its initial state

\dot{m} = 10 kg/s is water mass flow

For liquids, properties are evaluated as saturated liquid. From the figure attached, it can be seen that

h_f = 762.81 kJ/kg

h_i = 417.46 kJ/kg

Replacing

W = (762.81 kJ/kg - 417.46 kJ/kg) \times 10 kg/s

W = 3451 kJ/s

8 0
3 years ago
What are the three key things in science?
stiv31 [10]

Answer:

The three key things in Science are:

Physical Science,Earth Science and Life Science

If the answer helps you PLEASE mark me as brainliest

Stay Safe,Stay Healthy and Stay Happy

5 0
3 years ago
The molecular mass of octane is 114.22 g/mol. What is the mass of 22.05 mol of octane?
strojnjashka [21]
<span>In this item, we are asked to calculate for the mass of 22.05 mole of octane given that its molecular mass is equal to 114.22 g/mol. To answer this item, we simply have to multiply the number of moles with the molecular mass. That is, (114.22 g/mol)(22.05 mol) which is equal to 2518.221 grams. </span>
3 0
3 years ago
Read 2 more answers
In the coal-gasification process, carbon monoxide is converted to carbon dioxide via the following reaction: CO (g) H2O (g) CO2
jolli1 [7]

Answer: K_{eq} at  the temperature of the experiment is 0.56.

Explanation:

Moles of  CO = 0.35 mole

Moles of  H_2O = 0.40 mole

Volume of solution = 1.00 L

Initial concentration of CO = \frac{0.35mol}{1.00L}=0.35M

Initial concentration of H_2O = \frac{0.40mol}{1.00L}=0.40M

Equilibrium concentration of CO = \frac{0.19mol}{1.00L}=0.19M

The given balanced equilibrium reaction is,

                      CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)

Initial conc.          0.35 M         0.40 M                  0 M        0M

    At eqm. conc.     (0.35-x) M   (0.40-x) M   (x) M      (x) M

Given:  (0.35-x) = 0.19

x= 0.16 M

The expression for equilibrium constant for this reaction will be,

K_{eq}=\frac{[CO_2]\times [H_2]}{[CO]\times [H_2O]}  

Now put all the given values in this expression, we get :

K_{eq}=\frac{0.16\times 0.16}{(0.35-0.16)\times (0.40-0.16)}

K_{eq}=\frac{0.16\times 0.16}{(0.19)\times (0.24)}=0.56

Thus K_{eq} at  the temperature of the experiment is 0.56.

3 0
3 years ago
Which functional group is found in methyl ethanoate
Romashka [77]

Answer:

ester

Explanation:

methyl ethanoate is also known as methyl acetate

3 0
3 years ago
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