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3 years ago

All of the following elements produce magnetic fields except for

Physics

2 answers:

statuscvo [17]3 years ago

5 0

All of the following elements produce magnetic fields except for copper.

<h2>Further Explanation: </h2>

A magnet is an object that generates magnetic fields and therefore attracts magnetic materials such as nickel and iron.

<h3>Magnetic materials </h3>

Magnetic materials are those materials that are attracted by a magnet, they include, iron, nickel and cobalt.
Magnetic materials can be used to make magnets through the process of magnetization because they can produce magnetic fields.
Magnetic materials may be classified as paramagnetic materials and ferromagnetic materials.

Paramagnetic materials

They are materials that are not strongly attracted by a magnet. They include, magnesium and aluminium.
These materials can only be magnetized when placed on a very strong magnetic field.

2. Ferromagnetic materials

These are those materials that are strongly attracted by a magnet. They include iron, steel, cobalt, etc. Ferromagnetic materials may be soft or hard.
Soft ferromagnetic materials are those materials that can be easily magnetized such as iron and its alloy.
They can also be easily demagnetized, therefore making them suitable for use in electromagnets, transformers, generators, and telephone receivers among other devices.
They are used to make temporary magnets.
Hard ferromagnetic materials are those magnetic materials that are difficult to magnetize and demagnetize. They include, steel and cobalt. These materials are used to make permanent magnets and are suitable for use in devices such as speakers.

<h3>Non-magnetic materials </h3>

Non-magnetic materials on the other hand are those materials that cannot be attracted by a magnet. These material cannot produce magnetic fields.
They include, plastic, wood, rubber, water, etc. Non-magnetic materials cannot be used to make magnets.

Keywords: Magnets, magnetic materials, para-magnetic materials, ferro-magnetic materials

<h3>Learn more about </h3>

Magnetic materials: brainly.com/question/4240735
Examples of magnetic materials: brainly.com/question/4240735
Non-magnetic materials: brainly.com/question/4240735
Examples of non-magnetic materials: brainly.com/question/4240735

Magnetization: brainly.com/question/4240735

Level: High school

Subject: Physics

Topic: Magnetism

Subtopic: Magnetic and nonmagnetic materials.

Bogdan [553]3 years ago

3 0

The correct answer should be D. copper

Nickel, cobalt, and iron, produce magnetic fields when electrified while copper does not.

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Answer:

t = T/4

Explanation:

The power delivered to the mass by the spring is work done by the spring per second.

$P = \frac{dW}{dt}$

The work done by the spring is equal to the elastic potential energy stored in the spring.

$U = \frac{1}{2}kx^2$

The maximum energy stored in the spring is at the amplitude of the oscillation.

$U_{max} =\frac{1}{2}kA^2$

So the first time the mass reaches to its amplitude can be found by the following equation of motion:

$x = A\cos(\omega t + \phi)\\\phi = \pi/2 ~because ~at ~t= 0, ~ x = 0\\0 = A\cos(0 + \pi/2)\\x = A\cos(\omega t + \pi/2)$

When the mass reaches the amplitude:

$A = A\cos(\omega t + \pi/2)\\1 = \cos(\omega t + \pi/2)\\\omega t + \pi/2 = \pi$

because cos(π) = 1.

$\omega t = \pi/2$

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4 years ago

Which of the following describes one of the main features of wave-particle duality?

steposvetlana [31]

<h2>Answer: as mass increases, the wave nature of matter is less easy to observe.</h2>

At the beginning of the 20th century the French physicist Louis De Broglie proposed the existence of matter waves, that is to say that <u>all matter has a wave associated with it.</u>

In this sense, the de Broglie wavelength $\lambda$ is given by the following formula:

$\lambda=\frac{h}{p}$ (1)

Where:

$h$ is the Planck constant

$p$ is the momentum of the atom, which is given by:

$p=m.v$ (2)

Where:

$m$ is the mass

$v$ is the velocity

Substituting (2) in (1):

$\lambda=\frac{h}{m.v}[\tex] (3)As we can see, if we increase the mass, the wavelength decreases (because [tex]\lambda$ is inversely proportional to $m$ ).

Therefore, if the wavelength decreases the wave nature of matter is less easy to observe.

The other options are incorrect because:

a) as $v$ increases $\lambda$ decreases and the particle nature matter becomes more evident

b) as $p$ decreases $\lambda$ increases and the wave nature matter becomes more evident

c) There is also a relation between the wavelength and the energy $E$ :

$\lambda=\frac{hc}{E}$

So, as energy increases, the particle nature matter becomes more evident and the wave nature of matter becomes harder to observe

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Answer:

B. Parameter.

Explanation:

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Explanation:

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