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3 years ago

Find the length from a to c. Enter answer as a mixed number

Mathematics

1 answer:

Lilit [14]3 years ago

6 0

a to C would be 4 3/4 + 2/3

3/4 + 2/3 = 9/12 + 8/12 = 17/12 = 1 5/12

1 5/12 + 4 = 5 5/12 total distance

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A factory made 845 pairs of shoes in January. These shoes were sent to three shoe stores and one outlet mall. The number of pair

Semenov [28]

Answer=65 pairs of shoes

Given the data, the following equation can be made where x is equal to the number of shoes sent to the outlet mall.

845=4x+4x+4x+x
845=13x
divide both sides by 13
65=x

65 pairs of shoes were sent to the outlet mall

7 0

3 years ago

Read 2 more answers

How to differentiate y=x^n using the first principle. In this question, I cannot use the rule of differentiation. I have to do t

Zarrin [17]

By first principles, the derivative is

$\displaystyle\lim_{h\to0}\frac{(x+h)^n-x^n}h$

Use the binomial theorem to expand the numerator:

$(x+h)^n=\displaystyle\sum_{i=0}^n\binom nix^{n-i}h^i=\binom n0x^n+\binom n1x^{n-1}h+\cdots+\binom nnh^n$

$(x+h)^n=x^n+nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n$

where

$\dbinom nk=\dfrac{n!}{k!(n-k)!}$

The first term is eliminated, and the limit is

$\displaystyle\lim_{h\to0}\frac{nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n}h$

A power of $h$ in every term of the numerator cancels with $h$ in the denominator:

$\displaystyle\lim_{h\to0}\left(nx^{n-1}+\dfrac{n(n-1)}2x^{n-2}h+\cdots+nxh^{n-2}+h^{n-1}\right)$

Finally, each term containing $h$ approaches 0 as $h\to0$ , and the derivative is

$y=x^n\implies y'=nx^{n-1}$

4 0

3 years ago

HELP I NEED HELP ASAP

Paladinen [302]

<h2> <u>Rectangular</u> <u>Areas</u> <u>and</u> <u>Perimeters</u></h2>

The perimeter of a rectangle is given by:

$\boxed{\bold{Perimeter = 2 (length + width)}}$

In the problem we have these data:

Length = a

Width = -2x + 20

Perimeter = 6 + 2 (-2x + 20)

We replace the data in the equation of the perimeter:

We apply distributive property:

6 - 4x + 40 = 2a - 4x + 40

6 = 2a

6 ÷ 2 = a

3 = a

⇒ Length = 3

The area of the rectangle is given by:

$\boxed{\bold{Area = 2 (length + width)}}$

We have these data:

Length = 3

Width = -2x + 20

We replace the data in the equation of the area:

We apply the distributive property and obtain:

Area = -6x + 60

<u>The expression representing the area of the rectangle will be -6x + 60</u>

<h3>I hope I've helped!</h3>

8 0

3 years ago

3(12)=2(y-1) <br> *plzz answer my question*

Leona [35]

Step-by-step explanation:

3(12)=2(y-1)

36=2y-2

36+2=2y

38=2y(<em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>two</em><em>)</em>

y=19

7 0

3 years ago

Find the common ratio for the geometric sequence defined by the formula: an=40(2‾√)n−1 a n = 40 ( 2 ) n − 1

WITCHER [35]

The ratio of the geometric sequence 40 $2^{n-1}$ is 2.

Given that geometric sequence is 40* $2^{n-1}$ and we have to find the common ratio of all the terms.

Geometric sequence is a sequence in which all the terms have a common ratio.

Nth termof a GP is a $r^{n-1}$ in which a is first term and r is common ratio.

Geometric sequence=40* $2^{n-1}$

We have to first find the first term, second term and third term of a geometric progression.

First term=40* $2^{1-1}$

=40* $2^{0}$

=40*1

=40

Second term=40* $2^{2-1}$

=40* $2^{1}$

=40*2

=80

Third term=40* $2^{3-1}$

=40* $2^{2}$

=40*4

=160

Ratio of first two terms=80/40=2

Ratio of next two terms=160/80=2

Hence the common ratio of geometric sequence is 2.

Learn more about geometric progression at brainly.com/question/12006112

#SPJ1

4 0

2 years ago