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JulsSmile [24]
3 years ago
9

Draw the product you expect from the reaction of (s)-3-iodohexane with ch3co2-. be sure to show stereochemistry.

Chemistry
1 answer:
kodGreya [7K]3 years ago
8 0

A sub-discipline of chemistry, that is, stereochemistry includes the study of the comparative spatial alignment of atoms, which produce the composition of the molecules and their manipulation. The examination of stereochemistry aims at stereoisomers that by definition exhibits the similar sequence of bonded atoms and molecular formula, however, vary in the three-dimensional orientations of their atoms in space.  

The diagram is given in the attachment below:  


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cyclohexanol is burned as a fuel, according to the following equation, how many moles of oxygen are needed to produce 13.7 mol o
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 The moles  of oxygen  that are needed  to produce 13.7 moles  of  carbon  dioxide  is  21.17  moles  of Oxygen


<u><em>calculation</em></u>

2 C₆H₁₂O  + 17 O₂ → 12 CO₂  +12 H₂O


The moles of O₂  is determined using the mole ratio

that  is for  given equation above   O₂ : Co₂  is 17 :12

therefore the moles of O ₂= 13.7   moles x 17/12 =21.17  moles

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Answer:

8.37g

Explanation:

Step 1 :

The balanced equation for the reaction. This is given below:

N2 + 2O2 —> 2NO2

Step 2:

Data obtained from the question.

Volume (V) of N2 = 2L

Pressure (P) = 840mmHg

Temperature (T) = 24°C

Number of mole (n) of N2 =?

Step 3:

Conversion to appropriate unit.

For pressure:

760mmHg = 1atm

840mmHg = 840/760 = 1.11 atm

For Temperature:

T(K) = T(°C) + 273

T(°C) = 24°C

T(K) = 24°C + 273

T(K) = 297K

Step 4:

Determination of the number of mole N2.

The number of mole of N2 can be obtained by using the ideal gas equation as follow:

Volume (V) of N2 = 2L

Pressure (P) = 1.11 atm

Temperature (T) = 297K

Number of mole (n) of N2 =?

Gas constant (R) = 0.082atm.L/Kmol

PV = nRT

Divide both side by RT

n = PV / RT

n = 1.11 x 2 / 0.082 x 297

n = 0.091 mole

Therefore, the number of mole of N2 that reacted is 0.091 mole

Step 5:

Determination of the mass of NO2 produced from the reaction. This is illustrated below:

N2 + 2O2 —> 2NO2

From the balanced equation above,

1 mole of N2 produced 2 moles of NO2.

Therefore, 0.091 mole of N2 will produce = 0.091 x 2 = 0.182 mole of NO2.

Finally, we will convert 0.182 mole of NO2 to gram as shown below:

Number of mole NO2 = 0.182 mole

Molar mass of NO2 = 14 + (16x2) = 46g/mol

Mass = number of mole x molar mass

Mass of NO2 = 0.182 x 46

Mass of NO2 = 8.37g

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