Determine the oxidation number of chlorine in CI2 with the steps
1 answer:
Answer: The oxidation number of chlorine in is zero
Explanation:
Oxidation number or oxidation state : It represent the number of electrons lost or gained by the atoms of an element in a compound.
Rules for Oxidation Numbers are :
1. The oxidation number of a free element is always zero.
2. The oxidation number of a monatomic ion equals the charge of the ion.
3. The oxidation number of oxygen (O) in compounds is usually -2.
4. The oxidation number of a Group 17 element in a binary compound is -1.
5. The oxidation number of Hydrogen (H) is +1, but it is -1 in when combined with less electronegative elements.
6. The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
7. The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.
As exists as a free molecule, its oxidation state is zero.
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<u>Answer:</u> The correct statement is low temperature only, because entropy decreases during freezing.
<u>Explanation:</u>
The relationship between Gibb's free energy, enthalpy, entropy and temperature is given by the equation:
Where,
= change in Gibb's free energy
= change in enthalpy
T = temperature
= change in entropy
It is given that freezing of methane is taking place, which means that entropy is decreasing and is becoming negative. It is also given that the reaction is an exothermic reaction, this means that the
is also negative.
For a reaction to be spontaneous, must be negative.
From above equations, it is visible that will be negative only when the temperature will be low.
Hence, the correct statement is low temperature only, because entropy decreases during freezing.