Answer:
317 g
Explanation:
Cu + 2HCl --> CuCl2 +H2
1 : 2 1 : 1
1 mole of Cu = 63.5 g
1 mole of H2 = 2g
1 mole Cu produces = 1 mole of H2
63.5 g of Cu produces = 2 g of H2
So
10 g of H2 will be produced from = (63.5/2)*10 = 317 g of Copper
Answer:
rate = kxyz
Explanation:
It is worth knowing that the rate low can only be determined by experimentation only not by just balancing equations. So here we are told that all the reactants x , y and z are all first order. This is important because we use this as exponents. That is why the exponents of all the reactants will be 1.
rate = kxyz
Answer:
The combustion of hydrogen–oxygen mixtures is used to produce very high temperatures (approximately 2500 °C) needed for certain types of welding operations. Consider the reaction to be
H2(g)+1/2O2(g)=H2O(g)
change in enthalpy is -241.8 kJ
What is the quantity of heat evolved, in kilojoules, when a 160 g mixture containing equal parts of H2 and O2 by mass is burned?
Explanation:
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