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anzhelika [568]

3 years ago

5

How can a student use the diagram to calculate the atomic mass for the helium atom

1 answer:

djyliett [7]3 years ago

5 0

Answer:

Add G and H to determine the atomic mass for helium

Explanation:

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A sample of an unknown substance has a mass of 0.158 kg. If 2,510.0 J of heat is required to heat the substance from 32.0°C to 6

Alexxandr [17]

Specific heat capacity is the required amount of heat per unit of mass in order to raise teh temperature by one degree Celsius. It can be calculated from this equation: H = mCΔT where the H is heat required, m is mass of the substance, ΔT is the change in temperature, and C is the specific heat capacity.

H = m<span>CΔT
2501.0 = 0.158 (C) (61.0 - 32.0)

C = 545.8 J/kg</span>·°C

5 0

4 years ago

Suppose that 25.0 mL of 0.10 M CH3COOH (aq) is titrated with 0.10 M NaOH (aq). What is the pH after the addition of 10.0 mL of 0

olya-2409 [2.1K]

Answer:

$pH=-1.37$

Explanation:

We are given that 25 mL of 0.10 M $CH_3COOH$ is titrated with 0.10 M NaOH(aq).

We have to find the pH of solution

Volume of $CH_3COOH=25mL=0.025 L$

Volume of NaoH=0.01 L

Volume of solution =25 +10=35 mL= $\frac{35}{1000}=0.035 L$

Because 1 L=1000 mL

Molarity of NaOH=Concentration OH-=0.10M

Concentration of H+= Molarity of $CH_3COOH$ =0.10 M

Number of moles of H+=Molarity multiply by volume of given acid

Number of moles of H+= $0.10\times 0.025$ =0.0025 moles

Number of moles of $OH^-=0.10\times 0.01$ =0.001mole

Number of moles of H+ remaining after adding 10 mL base = 0.0025-0.001=0.0015 moles

Concentration of H+= $\frac{0.0015}{0.035}=4.28\times 10^{-2} m/L$

pH=-log [H+]=-log [4.28 $\times 10^{-2}$ ]=-log4.28+2 log 10=-0.631+2

$pH=-1.37$

6 0

3 years ago

Assume that coal can be represented by the chemical formula C135H96O9NS. If 4.0 tons of coal is burned, what mass of nitrogen is

Schach [20]

Answer:

0.02 tons of NO produced when 4 tons of coal is burned

Explanation:

From the given,

Chemical formula of coal = $C_{134}H_{96}O_{9}NS$

Molecular mass of coal = $(134\times12)+(9\times1)+(9\times16)+14+32\,=1906.1gm$

Let’s calculate the mass of nitrogen in coal

$Percentage\,weight\,of\,nitrogen=\frac{Mass\,of\,nitrogen}{Molecular\,mass\,of coal}$

$Percentage\,weight/,of/,nitrogen=\frac{14}{1906.1}=0.73%$

Amount of coal burnt = 4tons

Amount of NO produced by burning 4tons = $4\,tons\,of\,coal\times \frac{0.73tons}{100\,tons\,of\,coal}=0.0292\,tons$

This nitrogen is converted into NO by reacting with atmospheric oxygen.

8 0

3 years ago

Read 2 more answers

barxatty [35]

Answer:

it's food engineering obviously

4 0

4 years ago

klemol [59]

Answer:

D. Saline

Explanation:

coz it's saline

7 0

3 years ago

Read 2 more answers