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anzhelika [568]
3 years ago
5

How can a student use the diagram to calculate the atomic mass for the helium atom

Chemistry
1 answer:
djyliett [7]3 years ago
5 0

Answer:

Add G and H to determine the atomic mass for helium

Explanation:

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Metallic behavior is generally associated with elements with partially filled p orbitals. elements with unpaired electrons. elem
Mila [183]

Answer:

Elements with low ionization energies.

Explanation:

The ionization energy of an atom reffers to the amount of energy that is required to remove an electron from the gaseous form of that atom or ion.

The greater the ionization energy, the more difficult it is to remove an electron. The ionization energybis one of the indicator that shows the reactivity of an element. Elements with a low ionization energy such as metals are usually reffered to as a reducing agents and form cations, this give metals the tendency to

give away their valence electrons when bonding, whereas non-metals tend to take electrons.

Metallic elements have different properties such as shiny, heat and electricity conductivity . They are malleable and ductile Some metals, such as sodium, are soft and can be cut with a knife. while some are very hard such as iron.

4 0
3 years ago
The term for free electrons in metals transferring energy by colliding with other atoms or electrons is _____.
shepuryov [24]
Conduction

In metals, the electrons of each atom are delocalized, which means they are free to move about in the structure of the metal. When heat is applied at one end of the metal, the electrons there are excited and collide with surrounding particles, transferring their energy to them. This is what makes metals very good conductors of both heat and electricity. 
4 0
3 years ago
Read 2 more answers
After distilling your crude methyl benzoate, you set aside 4.83 grams of the purified ester. You then prepare the grignard reage
Ber [7]

Answer:

95.6 %

Explanation:

For this question, we will have <u>2 reactions</u>, the formation of the <u>grignard reagent</u> and the <u>formation of the alcohol</u>. The first step then is the calculation of the <u>maximum amount</u> of the grignard reagent. For this, we have to convert the grams to moles and check the smallest value. To do this we have to take into account the <u>following conversion ratios</u>:

Molar mass of Mg = 24 g/mol

Molar mass of phenylmagnesium bromide (C_6H_5Br)= 157 g/mol

Density of bromobenzene= 1.5 g/mL

Molar ratio between Mg and  C_6H_5Br= 1:1

2.3~g~Mg\frac{1~mol~Mg}{24~g~Mg}=0.096~mol~Mg

9.45~mL~\frac{1g}{1.5mL}\frac{1~mol~C_6H_5Br}{157~g}=0.0402~mol~C_6H_5Br

The smallest value is the mol of bromobenzene therefore <u>0.0402 mol</u> of phenylmagnesium bromide would be produced.

The next step is repite the same steps for the reaction of <u>formation of the alcohol</u>. Therefore we have to find the moles of methyl benzoate, so:

Molar mass of methyl benzoate: 136.14 g/mol

4.83~g~\frac{1~mol}{136.14~g}=0.35~mol

The we have to <u>divide by the coefficient</u> of each reactive in the balance reaction. So:

\frac{0.35~mol}{1}=0.35

\frac{0.0402~mol}{2}=0.0201

Therefore the <u>limiting reagent</u> would be the phenylmagnesium bromide. Now, the <u>molar ratio</u> between the phenylmagnesium bromide and triphenyl carbinol is <u>2:1</u>, so the amount of alcohol produced is 0.0201 mol triphenyl carbinol. The next step is the conversion from mol to <u>grams of triphenyl carbinol</u>:

Molar mass of triphenyl carbinol= 260.33 g/mol

0.0201~mol\frac{260.33~g}{1~mol}=5.23~g~triphenyl carbinol

Finally, we have to <u>divide</u> the obtanied solid by the calculated one:

Percentage=\frac{5}{5.23}*100=95.6\%

5 0
3 years ago
What are three of Leonardo divinci's contributions to science?
Zielflug [23.3K]
<span> hydraulic pumps, flying machines, and war machines.</span>
5 0
3 years ago
What is the wavelength in nm of a light whose first order bright band forms a
miskamm [114]

Answer:

714 nm

Explanation:

Using the equation: nλ=d<em>sin</em>θ

where

n= order of maximum

λ= wavelength

d= distance between lines on diffraction grating

θ= angle

n is 1 because the problem states the light forms 1st order bright band

λ is unknown

d=  \frac{1}{700,000} or 0.0000014 (meters)

sin(30)= 0.5

so

(1)λ=(0.0000014)(0.5)

=0.000000714m or 714 nm

3 0
3 years ago
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