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liq [111]
3 years ago
8

Which if the following rules best describes the matrix below?

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
5 0

i think A because delation of scale factor 2

marissa [1.9K]3 years ago
4 0

Answer:

B reflection over the y-axis

Step-by-step explanation:

I took the test and got it correct

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Please help me on this​
alexdok [17]

Answer:

-6|5

Can I maybe be Brainliest

have a nice day Best regards

5 0
3 years ago
Read 2 more answers
300€ durante 5 años al 0.3% de interés compuesto mensual. A) ¿Cuánto interés se ha ganado? B) Cuánto interés se ha ganado?
marysya [2.9K]

Answer:

Interes ganado= €59.07

Step-by-step explanation:

Dada la siguiente informacion:

300€ durante 5 años al 0.3% de interés compuesto mensual.

<u>Para calcular el valor final de la inversión y el interés ganado, debemos usar la siguiente formula:</u>

FV= PV*(1 + i)^n

Present Value= 300

i= 0.003

n= 5*12= 60 meses

FV= 300*(1.003^60)

FV= 359.07

Interes ganado= 359.07 - 300

Interes ganado= 59.07

5 0
3 years ago
Can someone help me please
Darya [45]

Answer:

a^7/b^6

Step-by-step explanation:

3 0
3 years ago
What is the 4(4x)+(x) equal!?
e-lub [12.9K]

4(4x)+(x)

= 16x+x

Combine like terms

16x+x

(16x+x)

= 17x

x=17


I hope that's help ! Good night .

5 0
3 years ago
A circle is centered at J(3, 3) and has a radius of 12.
stealth61 [152]

Answer:

(-6,\, -5) is outside the circle of radius of 12 centered at (3,\, 3).

Step-by-step explanation:

Let J and r denote the center and the radius of this circle, respectively. Let F be a point in the plane.

Let d(J,\, F) denote the Euclidean distance between point J and point F.

In other words, if J is at (x_j,\, y_j) while F is at (x_f,\, y_f), then \displaystyle d(J,\, F) = \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}.

Point F would be inside this circle if d(J,\, F) < r. (In other words, the distance between F\! and the center of this circle is smaller than the radius of this circle.)

Point F would be on this circle if d(J,\, F) = r. (In other words, the distance between F\! and the center of this circle is exactly equal to the radius of this circle.)

Point F would be outside this circle if d(J,\, F) > r. (In other words, the distance between F\! and the center of this circle exceeds the radius of this circle.)

Calculate the actual distance between J and F:

\begin{aligned}d(J,\, F) &= \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}\\ &= \sqrt{(3 - (-6))^{2} + (3 - (-5))^{2}} \\ &= \sqrt{145}  \end{aligned}.

On the other hand, notice that the radius of this circle, r = 12 = \sqrt{144}, is smaller than d(J,\, F). Therefore, point F would be outside this circle.

5 0
3 years ago
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