The question is incomplete, here is the complete question:
A(aq) + B(aq) → 2C(aq)
If the value of Kc for the reaction is 434, what is the concentration of C at equilibrium if initial concentrations of A and B are both 0.500 M. (Hint: Everything is squared after you set-up the equilibrium expression with the values given.
<u>Answer:</u> The concentration of C at equilibrium is 0.912 M
<u>Explanation:</u>
We are given:
Initial concentration of A = 0.500 M
Initial concentration of B = 0.500 M
The given equation follows:
<u>Initial:</u> 0.5 0.5
<u>At eqllm:</u> 0.5-x 0.5-x 2x
The expression of for above equation follows:
We are given:
Putting values in above equation, we get:
Neglecting the value of x = 0.553 M because the equilibrium concentration of A and B will become negative, which is not possible
So, equilibrium concentration of C = 2x = 2(0.456) = 0.912 M
Hence, the concentration of C at equilibrium is 0.912 M