2NaOH(aq) + H2SO4(aq) => Na2SO4(s) + 2H2O(l)
This is a neutralization reaction.
Answer:
After 26.0s, the concentration of HI decreases from 0.310M to 0.0558M.
Explanation:
Based on the reaction of the problem, you have as general kinetic law for a first-order reaction:
ln[HI] = -kt + ln [HI]₀
<em>Where [HI] is actual concentration after time t, </em>
<em>k is rate constant </em>
<em>and [HI]₀ is initial concentration of the reactant.
</em>
Initial concentration of HI is 0.310M,
K is 0.0660s⁻¹,
And the actual concentration is 0.0558M:
ln[HI] = -kt + ln [HI]₀
ln[0.0558M] = -0.0660s⁻¹*t + ln [
0.310M]
-1.7148 = -0.0660s⁻¹*t
26.0s = t
<h3>After 26.0s, the concentration of HI decreases from 0.310M to 0.0558M</h3>
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