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harina [27]
2 years ago
11

For the last question, this is my data

Chemistry
1 answer:
Lena [83]2 years ago
5 0

Answer:

Noble gases:

 are highly reactive.

 react only with other gases.

 do not appear in the periodic table.

 are not very reactive with other elements.

Explanation:Noble gases:

 are highly reactive.

 react only with other gases.

 do not appear in the periodic table.

 are not very reactive with other elements.

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What sequence of DNA bases bond with the DNA base sequence ATGT
Paha777 [63]

Answer:

DNA bases bonds with each other in this sequence

Explanation:

Guanine bonds triple  bonds with cytosine respectively while Adenine bonds double bond with thymine .

3 0
3 years ago
To measure the amount of nickel in some industrial waste fluid, an analytical chemist adds sodium hydroxide solution to a sample
Cloud [144]

Answer:

The final balanced equation is

Ni2+ + 2NaOH --> Ni (OH)2 + 2Na+

Explanation:

It is given that sodium hydroxide is added to collect the solid nickel(II) hydroxide product

The empirical equation for this statement is

Ni2+ + NaOH --> Ni (OH)2 + Na+

We will first balance the hydroxide molecule. On the right side there are two OH molecules.

Thus, on the left side we will take 2 sodium hydroxide

Ni2+ + 2NaOH --> Ni (OH)2 + Na+

Now we will balance the sodium ion which are 2 in numbers on the left side and 1 on the right side

Ni2+ + 2NaOH --> Ni (OH)2 + 2Na+

So, the final balanced equation is

Ni2+ + 2NaOH --> Ni (OH)2 + 2Na+

8 0
3 years ago
Which of the analogies below is a location-based analogy?
nydimaria [60]
D is the correct answrt
4 0
3 years ago
This chart shows descriptions of the atoms for four different substances.
Whitepunk [10]
I think it’s Object 3
Hopefully this helps
8 0
3 years ago
The ka of acetic acid ch3co2h is 1.8 x10-5. what is the ph
AysviL [449]
You must know the concentration of the acetic acid. Suppose the concentration is 0.1 M. The solution is as follows:

            CH₃COOH → CH₃COO⁻ + H⁺
 I                  0.1               0              0
C                 -x                +x            +x
E              0.1 - x             x               x

Ka = (x)(x)/(0.1 - x)
1.8×10⁻⁵ = x²/(0.1 - x)
Solving for x,
x = 1.333×10⁻³ = H⁺

pH = -log[H⁺] = -log(1.333×10⁻³)
pH = 2.88

6 0
3 years ago
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