Describe how a baseball player accelerates as he runs around the bases after hitting home run

1 answer:

4 0

he accelerates when he runs away from home plate. as he reaches each base, the player accelerates by changing direction. he accelerates again when slowing down after reaching home plate.

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A salt shaker filled with 17.0g sodium chloride contain how many moles?

kati45 [8]

The molecular formula for sodium chloride is NaCl. The sum of their atomic weights is (22.99 grams/mole + 35.45 grams/mole) = 58.44 grams/mole
take (17.0 grams)/(58.44 grams/mole), which equals 0.291 moles of NaCl.

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3 years ago

What would the formula of gallium bromide be?

Free_Kalibri [48]

GaBr3

Gallium=Ga
Bromine= Br
Bromide=Br3

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3 years ago

How many salt and water would you use to prepare 10% salt solution?

tatuchka [14]

Answer:

We can make 10 percent solution by volume or by mass. A 10% of NaCl solution by mass has ten grams of sodium chloride dissolved in 100 ml of solution. Weigh 10g of sodium chloride. Pour it into a graduated cylinder or volumetric flask containing about 80ml of water.

Explanation:

have a good day

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3 years ago

Give me a statement regarding the process of science discovery and development of atomic theory

matrenka [14]

Can you say please? Just kidding!
The process of science discovery depends upon changing your theories based upons new evidence from new experiments. New technology allows for new experiments, leading to new theories.

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3 years ago

Natural gas is almost entirely methane. A container with a volume of 2.65L holds 0.120mol of methane. What will the volume be if

mrs_skeptik [129]

The final volume of the methane gas in the container is 6.67 L.

The given parameters;

initial volume of gas in the container, V₁ = 2.65 L
initial number of moles of gas, n₁ = 0.12 mol
additional concentration, n = 0.182 mol

The total number of moles of gas in the container is calculated as follows;

$n_t = 0.12 + 0.182 = 0.302 \ mol$

The final volume of gas in the container is calculated as follows;

$PV = nRT\\\\\frac{V}{n} = \frac{RT}{P} \\\\\frac{V_1}{n_1} = \frac{V_2}{n_2} \\\\V_2 = \frac{V_1 n_2}{n_1} \\\\V_2 = \frac{2.65 \times 0.302}{0.12} \\\\V_2 = 6.67 \ L$

Thus, the final volume of the methane gas in the container is 6.67 L.

Learn more here:brainly.com/question/21912477

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3 years ago