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Yanka [14]
4 years ago
8

Describe the possible components of a buffer solution. (Select all that apply.)

Chemistry
1 answer:
AlexFokin [52]4 years ago
7 0

Both D and G options. Weak base and its conjugate acid or weak acid and its conjugate base are the possible components of a buffer solution.

Explanation:

Buffer solution is the solution which gets easily dissolved in water and so called as "Aqueous solution".

Buffer solution is essentially made up of two components Known as:

i.) Weak base and its conjugate acid

ii.) Weak acid and its conjugate base

This weak acid and base solution is used to maintain the pH value of the solution in a balanced way.

When the weak acid or base solution is added to strong acid or base solution that is the way pH gets balanced .

In one word buffer solution is the solution which resists for the pH change when strong acids or bases are added.

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A solution is prepared by dissolving 0.24 mol of butanoic acid and 0.25 mol of sodium butanoate in water sufficient to yield 1.0
beks73 [17]

Answer:

Butanoic acid present in solution

Explanation:

In this case, we have a buffer solution of butanoic acid and sodium butanoate.  In other words a reaction like this:

HC₄H₇O₂ + H₂O <------> C₄H₇O₂⁻ + H₃O⁺   Ka = 1.5x10⁻⁵

The low value of Ka means that this is a weak acid. So, after this, the NaOH is added to the solution.

The NaOH is a really strong base, so we might expect that the pH of the solution increase drastically, however this do not occur.

The reason for this is because the first thing to happen in this reaction is an acid base reaction.

The NaOH react with the butanoic acid still present in solution, because is a weak acid, so in solution, this acid is not completely dissociated into it's respective ions. So the butanoic acid reacts with the NaOH and the products:

HC₄H₇O₂ + NaOH <------> Na⁺C₄H₇O₂⁻ + H₂O

So, because of this, the pH increase but not much.

6 0
3 years ago
Select the correct answer. If the EMF produced in a wire is 0.88 volts and the wire moves perpendicular to a magnetic field of s
serious [3.7K]

<u>Given:</u>

EMF = 0.88 V

Strength of magnetic field, B = 0.075 N/A-m

Velocity, v = 4.20 m/s

<u>To determine:</u>

The length of wire, L

<u>Explanation:</u>

The EMF is related to strength of the magnetic field B as:

EMF = L*B*v

L = EMF/B*v = 0.88/0.075*4.20 = 2.79 m

Ans: The length of the wire is around 2.8 m


3 0
3 years ago
How many moles of acetylene are needed to completely react with 16.5g of CO2
kykrilka [37]

Answer:

0.375 mols

Explanation:

  1. Relative atomic mass Ar of C=12×1=12
  2. Relative atomic mass Ar of O=16×2=32
  3. Realitive formula mass Mr is 12+32=44

mol:mass

1 : 44

x :16.5

cross multiply and get the answer

5 0
3 years ago
Help me ASAP !!!!!!!!!!
lapo4ka [179]

Answer:

metallic

Explanation:

3 0
3 years ago
When the following solutions are mixed together, what precipitate (if any) will form? a. FeSO4(aq) 1 KCl(aq) b. Al(NO3)3(aq) 1 B
noname [10]

Answer: Precipitates form only in (b) (c) and (d) and these are Al(OH)_3  , CaSO_4 and NiS respectively.

Explanation: (a) The reaction will be:

FeSO_4(aq)+2KCl(aq)\rightarrow FeCl_2(aq)+K_2SO_4(aq)

The reaction will not take place as both the products are soluble and so no precipitate will form.

(b) The reaction will be:

2Al(NO_3)_3(aq)+3Ba(OH)_2(aq)\rightarrow 3Ba(NO_3)_2(aq)+2Al(OH)_3(s)

This reaction will take place as aluminum hydroxide is insoluble. So, the precipitate formed in this reaction is Al(OH)_3 .

(c) The reaction will be:

CaCl_2(aq)+Na_2SO_4(aq)\rightarrow 2NaCl(aq)+CaSO_4(s)

This reaction will take place as a precipitate of calcium sulfate(slightly soluble) will form.

(d) The reaction will be:

K_2S(aq)+Ni(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+NiS(s)

This reaction will take place as NiS is insoluble. So, the precipitate formed in this reaction is NiS.

8 0
3 years ago
Read 2 more answers
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