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3 years ago

Describe the possible components of a buffer solution. (Select all that apply.)

1 answer:

7 0

Both D and G options. Weak base and its conjugate acid or weak acid and its conjugate base are the possible components of a buffer solution.

Explanation:

Buffer solution is the solution which gets easily dissolved in water and so called as "Aqueous solution".

Buffer solution is essentially made up of two components Known as:

i.) Weak base and its conjugate acid

ii.) Weak acid and its conjugate base

This weak acid and base solution is used to maintain the pH value of the solution in a balanced way.

When the weak acid or base solution is added to strong acid or base solution that is the way pH gets balanced .

In one word buffer solution is the solution which resists for the pH change when strong acids or bases are added.

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PLZ HELP THERE IS A FILE ATTACHED WILL GIVE U BRAINLIEST IF U HELP

erastovalidia [21]

Answer:

I think C (Might not be true)

Explanation:

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3 years ago

Read 2 more answers

Which of these metals reacts more vigorously with water? 1. Zinc 2. Magnesium

GalinKa [24]

Answer:

magnesium

Explanation:

because zinc does not react with water because it too forms a protective layer of insoluble.

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3 years ago

What is the molarity of a solution that contains 4.3 mol of acetic acid (C2H3O2) in 450. mL of solution?

lord [1]

Hey there !

Number of moles of solution: 4.3 moles

Volume in liters:

450.0 mL / 1000 => 0.45 L

Therefore:

Molarity = number of moles / volume of solution ( L)

Molarity = 4.3 / 0.45

=> 9.55 M

Hope that helps!

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3 years ago

How glass tube filed with acidified potassium dichromate detect drunken driver

hodyreva [135]

Answer:

See explanation

Explanation:

The reaction between alcohol and acidified potassium dichromate is a redox reaction. This reaction can be used to detect a drunken driver.

Alcohols can be oxidized to aldehydes, ketones and carboxylic acids depending on the structure of the alcohol. Primary alcohols yield adehydes and carboxylic acids while secondary alcohols are oxidized to ketones.

The colour of the acidified potassium dichromate turns from orange to green when exposed to alcohols from the breath of a drunken driver.

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3 years ago

Assume that you have a cylinder with a movable piston. What would happen to the gas pressure inside the cylinder if you do the f

pishuonlain [190]

Answer:

A. The pressure will increase 4 times. P₂ = 4 P₁

B. The pressure will decrease to half its value. P₂ = 0.5 P₁

C. The pressure will decrease to half its value. P₂ = 0.5 P₁

Explanation:

Initially, we have n₁ moles of a gas that occupy a volume V₁ at temperature T₁ and pressure P₁.

What would happen to the gas pressure inside the cylinder if you do the following?

Part A: Decrease the volume to one-fourth the original volume while holding the temperature constant. Express your answer in terms of the variable P initial.

V₂ = 0.25 V₁. According to Boyle's law,

P₁ . V₁ = P₂ . V₂

P₁ . V₁ = P₂ . 0.25 V₁

P₁ = P₂ . 0.25

P₂ = 4 P₁

Part B: Reduce the Kelvin temperature to half its original value while holding the volume constant. Express your answer in terms of the variable P initial.

T₂ = 0.5 T₁. According to Gay-Lussac's law,

$\frac{P_{1}}{T_{1}} =\frac{P_{2}}{T_{2}}\\\frac{P_{1}}{T_{1}} =\frac{P_{2}}{0.5T_{1}}\\\\P_{2}=0.5P_{1}$

Part C: Reduce the amount of gas to half while keeping the volume and temperature constant. Express your answer in terms of the variable P initial.

n₂ = 0.5 n₁.

P₁ in terms of the ideal gas equation is:

$P_{1}=\frac{n_{1}.R.T_{1}}{V_{1}}$

P₂ in terms of the ideal gas equation is:

$P_{2}=\frac{n_{2}.R.T_{1}}{V_{1}}=\frac{0.5n_{1}.R.T_{1}}{V_{1}}=0.5P_{1}$

3 0

3 years ago