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3 years ago

Describe the possible components of a buffer solution. (Select all that apply.)

1 answer:

7 0

Both D and G options. Weak base and its conjugate acid or weak acid and its conjugate base are the possible components of a buffer solution.

Explanation:

Buffer solution is the solution which gets easily dissolved in water and so called as "Aqueous solution".

Buffer solution is essentially made up of two components Known as:

i.) Weak base and its conjugate acid

ii.) Weak acid and its conjugate base

This weak acid and base solution is used to maintain the pH value of the solution in a balanced way.

When the weak acid or base solution is added to strong acid or base solution that is the way pH gets balanced .

In one word buffer solution is the solution which resists for the pH change when strong acids or bases are added.

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<h3>Further explanation</h3>

Given

Reaction

3H₂(g) + N₂(g) ⇒ 2NH₃(g)

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Required

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Consider the reaction between iodine gas and chlorine gas to form iodine monochloride. A reaction mixture at 298.15k initially c

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Step 1 : Write balanced chemical equation

The balanced chemical equation for the reaction between iodine gas and chlorine gas is given below.

$I_{2} (g) + Cl_{2} (g) -----> 2 ICl (g)$

Step 2 : Set up ICE table

We will set up an ICE table for the above reaction

Following points are considered while drawing ICE table

- The initial concentration of product is assumed as 0

- The change in concentration (C) is assumed as x. Change (x) is negative for reactants and positive for products

- The coefficients in balanced equation are considered while writing C values

Check attached file for ICE table

Step 3 : Set up equilibrium constant equation

The equation for equilibrium constant can be written as

$K_{eq} = \frac{[ICl]^{2}}{[I_{2}][Cl_{2}]}$

Step 4 : Solving for x

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Let us plug in the equilibrium values (E) for I₂, Cl₂ and ICl from ICE table

81.9 = $\frac{(2x)^{2}}{(0.437-x) (0.269-x)}$

81.9 = $\frac{(2x)^{2}}{x^{2} -0.706x + 0.118}$

$(2x)^{2} = 81.9 [ x^{2} -0.706x + 0.118]$

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Solving the above equation using quadratic formula we get

x = 0.488 or x = 0.254

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