What is the average velocity of atoms in 1.00 mol of argon (a monatomic gas) at 275 k for m, use 0.0399kg
Answer: The average velocity of the atoms 847.33 m/s.
Explanation:
Moles of the neon = 1.00
Temperature of the gas : 288 K
Mass of the gas = 0.01000
R = 8.31 J/mol K
The average velocity of the atoms 847.33 m/s.
D = m / V
d = 1300 g / 743 cm³
d = 1.749 g/cm³
The answer is: A) Na3PO4 + 3KOH → 3NaOH + K3PO4, because K retains the same charge throughout the reaction.
This chemical reaction is double displacement reaction - cations (K⁺ and Na⁺) and anions (PO₄³⁻⁻ and OH⁻) of the two reactants switch places and form two new compounds.
Na₃PO₄ is sodium phosphate.
KOH is potassium hydroxide.
NaOH is sodium hydroxide.
K₃PO₄ is potassium phosphate.
According to the mass conservation law, there are same number of atoms on both side of balanced chemical reaction.
