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bonufazy [111]
3 years ago
14

Why should you label your plates on the bottom instead on the lid?

Chemistry
1 answer:
KengaRu [80]3 years ago
3 0
A. To prevent contamination
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Linked-up atoms form matter called?
Salsk061 [2.6K]

Answer:

compound

Explanation:

7 0
3 years ago
How can mixtures best be described?
anygoal [31]
Mixtures are unlike chemical compounds, because: The substances in a mixture can be separated using physical methods such as filtration, freezing, and distillation. ... When mixed, individual substances keep their properties in a mixture, while if they form a compound their properties can change.
4 0
3 years ago
Read 2 more answers
A chemistry student needs 15.0 g of methanol for an experiment. She has available 320. g of 44.4% w/w solution of methanol in wa
Makovka662 [10]

Answer:

33.8 g Solution

Explanation:

A chemistry student needs 15.0 g of methanol for an experiment. The concentration of ethanol in the solution is 44.4% w/w, that is, there are 44.4 g of methanol every 100 g of solution. The mass of solution that would contain 15.0 g of methanol is:

15.0 g Methanol × 100 g Solution/44.4 g Methanol = 33.8 g Solution

Since 33.8 g are required and 320. g are available, there is enough solution for the requirements.

4 0
3 years ago
a 1.00-l solution contains 2.50×10-4 m cu(no3)2 and 1.20×10-3 m ethylenediamine (en). the kf for cu(en)22 is 1.00 × 1020. chegg
Debora [2.8K]

The concentration of copper in the solution is

5.1 \times 10^{18}  \: M.

The volume of the solution = 1.00 L

Moles \: of \:Cu(NO_{3}) _{2} = 2.50 \times 10 {}^{ - 4}

Moles \:  of  \: Ethylenediamine = 1.20 \times 10.3

k _{f} = 1.00 \times 10^{20}

Overall balanced equation of reaction is,

Cu^{2 + }(aq)  \:  + 2en \: (aq)→ Cu(en) ^{2 + }_{2}(aq)

Moles \: of \:Cu(NO_{3}) _{2} =0.00025 \: mol

Mole ratio for,

Moles \: of\:Cu(NO_{3}) _{2}: en

2: 1

Moles \: of \: en = 0.000250 \times 2

= 0.00050 \: moles

Remained moles of en are= (0.00120-0.000500)

= 0.000700 \: moles

The concentration of copper in the solution is,

k_{f} =  \frac{Cu(en)^{2 + }_{2}  }{Cu^{2+}en^{2}  }

1.00 \times 10 ^{20} =  \frac{0.000250}{(Cu )^{2 +}  \times (0.000700)^{2 + } }

=  5.1 \times 10^{18}  \: M.

Therefore, the concentration of copper in the solution is

5.1 \times 10^{18}  \: M.

To know more about molarity, refer to the below link:

brainly.com/question/8732513

#SPJ4

4 0
2 years ago
Neeeeeed helpppppp will give brainiest
Artyom0805 [142]

Answer:

I think it is c

Explanation:

When water turns into water vapor it goes into the air so it must be lighter

5 0
3 years ago
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