B. A car moving at an initial speed vi applies its brakes and skids for some distance until coming to a complete stop. If the co
efficient of kinetic friction between tires and the road is µk what distance did the car skid?
1 answer:
Complete Question
The complete question is shown on the first uploaded image
Answer:
The distance which the car skid is
Explanation:
From the question we are told that
The initial velocity of the car is
The coefficient of kinetic friction is
According to the law of energy conservation
The initial Mechanical Energy = The final Mechanical Energy
The initial mechanical energy is mathematically represented as
where KE is the initial kinetic energy which is mathematically represented as
And PE is the initial potential energy which is zero given that the car is on the ground
Now
Where is the work which friction exerted on the car which is mathematically represented as
Where is the distance covered by the car before it slowed down
=>
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During a rodeo, a clown runs 7.7 m north, turns 49.9 degrees east of north, and runs 6.4 m. Then after waiting for the bull to come near, the clown turns due east and runs 19.8 m to exit the arena. The magnitude of the clown’s displacement is 27 m.
<u>Explanation: </u>
As the clown is running in the north direction for about 7.7 m and then he turns 49.9 degrees east of north. In the east of north, he covers a distance of 6.4 m and then turns east to exit the arena after covering a distance of 19.8 m. Let’s have a simple diagram to easily understand the problem.
In first step, the clown runs 7.7 m in north direction, so the image will be as in fig 1. Then he takes a direction of north east and covers a distance of 6.4 m, so the image will be modified as in fig 2. Then after the bull comes, he turns east and runs 19.8 m to exit the arena, so the image will be as in figure 3.
So, the extension of North line and the East line at a point shown as the dotted line in the above image, forms the total displacement as the hypotenuse of a right angled triangle. The extended dotted lines is nothing but the horizontal and vertical components of the angle 49.9 degree.
By using Pythagoras theorem, the total displacement can be found as
Similarly, the adjacent side of this imaginary triangle is the distance covered by the clown in the North direction.
Thus, the total displacement covered by the clown is
Thus, the total displacement by the clown is 27 m.
