Using
F= mv²/r
4 = 0.5×v² / 2
8 /0.5 = v²
v²=16
v= √16
v= 4 ms-¹
We can solve the problem by applying Newton's second law, which states that the force F applied on the system (man+bycicle) is equal to the product between the mass of the system, m, and its acceleration, a:
In this problem, we know the force applied (F=100 N), and the mass of the system man+bycicle (m=80 kg). Therefore, we can rearrange the previous formula to calculate the acceleration of the system:
Answer:
Q = 12540 J
Explanation:
It is given that,
Mass of water, m = 50 mL = 50 g
It is heated from 0 degrees Celsius to 60 degrees Celsius.
We need to find the energy required to heat the water. The formula use to find it as follows :
Where c is the specific heat of water, c = 4.18 J/g°C
Put all the values,
So, 12540 J of energy is used to heat the water.
Answer:
The coefficient of kinetic friction between the block and the surface is 0.5
Explanation:
It is given that,
Initial velocity of the block, u = 10 m/s
Time taken by the block to come to rest, t = 2 s
So, final velocity, v = 0
We need to find the coefficient of kinetic friction between the block and the surface. According to second law of motion :
F = ma
And friction force F = -μmg
i.e.
...........(1)
Firstly, we will find the value of a i.e. acceleration
a = -5 m/s²
So, equation (1) becomes :
So, the coefficient of kinetic friction between the block and the surface is 0.5. hence, this is the required solution.
Answer
given,
current, I = 3.7 A
width of conductor = 1.5 cm
Length = 4 cm
thickness = 12 μm
hall potential difference = 78 μV
magnetic field = 0.76 T
a) drift velocity of the charge carrier
number density of charge carrier
n = 1.878 x 10²⁸ electrons/m³