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Nadya [2.5K]
2 years ago
15

100 Points!!!

Physics
1 answer:
Kaylis [27]2 years ago
4 0

(1) The image of an object placed further from the lens than the focal point will be upside down and smaller than the object.

(2) When light rays reflect, they bounce back.

(3)  Images formed by a concave lens will look magnified.

(4) When light rays enter a different medium, they bend.

<h3>1.0 Object placed further from the lens than the focal point</h3>

The image of an object placed further from the lens than the focal point will be diminished and inverted.

Thus, the correct answer will be "upside down and smaller than the object".

<h3>2.0 What is reflection of light?</h3>

The ability of light to bounce back when it strike a hard surface is known as refection.

<h3>3.0 Image formed by concave lens</h3>

A concave lens is diverging lens is usually virtual, erect and magnified.

<h3>4.0 Refraction of light</h3>

The change in speed of light when it travels from medium to another medium is known as refraction. Refraction is also, the ability of light to bend around obstacles.

Learn more about reflection and refraction of light here: brainly.com/question/1191238

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Concerning the work done by a conservative force, which of the following statements, if any, are true? It can always be expresse
Vera_Pavlovna [14]

Answer:

It is independent of the path of the body and depends only on the starting and ending points.

Explanation:

In Physics we define a conservative force as a force that is independent of the path of the body and depends only on the starting and ending points.

For conservative forces we can write;

KEi + PEi = KEf +PEf

where;

KEi= initial kinetic energy

PEi= initial potential energy

KEf= final kinetic energy

PEf= final potential energy

This equation is known as the principle conservation of mechanical energy . It applies only to conservative forces where friction is negligible. The term KE + PE  is also known as the total mechanical energy of the system.

3 0
4 years ago
At a maximum level of loudness, the power output of a 75-piece orchestra radiated as sound is 72.0 W. What is the intensity of t
FrozenT [24]

Answer:

<em> The intensity would be 0.01432 W/</em>m^{2}<em></em>

Explanation:

The sound intensity is the power that is transmitted by a sound wave per unit area.

Given that

Power output P of the 75-piece orchestra = 72.0 W

The listener's distance  r = 20.0 m

The intensity of sound waves (I) can be obtained with the expression below;

I = P/A .............. 1

where P is the power

A is the area, in this case, at the distance r the sound is radiated through  a sphere.

A = area of a sphere = 4πr^{2}

putting it into equation 1, the intensity would be;

I = P/ 4πr^{2}

Substituting our values we have;

I = 72.0 W /  4 π 20^{2} m^{2}

I = 0.01432 W/m^{2}

Therefore the intensity would be 0.01432 W/m^{2}

3 0
3 years ago
Help me for my homework
Serggg [28]
20 cm = bright
40 cm = dim
The longer the wire the bigger the resistance
5 0
3 years ago
Which only list metalloids
HACTEHA [7]

Answer: I think the answer <em><u>MIGHT</u></em> be: Boron, germanium, and tellurium....

Explanation:I know this cuz I had this question on my unit test and I had to look it up online....Hope this helps

I really hope you guys find this helpful and thx so much for rating :D

       pls say something in chat if you found this helpful

                                              UwU           ;-;

                                                         

7 0
3 years ago
A solid disk of radius 5.50 cm and mass 1.25 kg , which is rolling at a speed of 1.50 m/s , begins rolling without slipping up a
shtirl [24]

Answer:

Explanation:

Deceleration of solid disk = g sin10/1 + k²/r² = g sin 10 / 1 + 1/2 = g sin 10 x 2/3

[ k is radius of gyration of disk which is equal to( 1/√2)x r ]

deceleration a = -1.1345 m/s²

v = u - at , t = u / a = 1.5 / 1.1345 = 1.322 s.

5 0
3 years ago
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