If this question has the same set of options as to the following, the answer would be letter d. Continuity.
Continuity in Psychology accounts for visual perception of immediate environments that piece together a background's individual elements to form a panoramic image.<span> </span>
The choices are:
A.) depth perception.
<span>B.) perception. </span>
<span>C.) similarity. </span>
<span>D.) continuity.
</span>
Answer: x= 75
Explanation:1x -3y = 30
And y = 15
Substitute y accordingly into the equation, so that
x - 3(15) = 30
x-45=30
Add 45 to both sides if the equation
x-45+45=30+45
x=75
Answer:
Part A:

Part B:
Magnitude of displacement=44.721359 m
Explanation:
Given Data:
40 m in negative direction of the x axis
20 m perpendicular path to his left (considering +ve y direction)
25 m up a tower (Considering +ve z direction)
Required:
- In unit-vector notation, what is the displacement of the sign from start to end.
- The magnitude of the displacement of the sign from start to this new end=?
Solution:
Part A:

where:
i,j,k are unit vectors
Part B:
Sign falls to foot of tower so z=0

Magnitude of displacement:

Answer:
a) v=1.36f
b)m=.36
c) real
d) Inverted
Explanation:
a)
In this question we have given,
object distance from converging lens,u=-3.78f
focal length of converging lens,=f
we have to find location of image,v=?
and magnification,m=?
we know that u, v and f are related by following formula
.............(1)
put values of f u in equation (1)
we got,



or
v=1.36f
b) Magnification, 
c)
Here the object is located further away from the lens than the focal point therefore image is real image and inverted.
d) image is inverted
Answer:
El índice es la tabla de contenidos de un documento. El desarrollo es el cuerpo de información contenida en un documento
Explanation: