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pantera1 [17]
3 years ago
11

A car travels along highway with a speed of 36 km/h. Find out the distance

Physics
1 answer:
Black_prince [1.1K]3 years ago
5 0

Please find attached photograph for your answer. Hope it helps. Please do comment

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Help with these please?
Anuta_ua [19.1K]

E=kq/r^2

q=(E*r^2)/k

q=(.086N/C)(1.7m^2)/(8.99*10^9N*m^2/C^2)

q=2.76*10^-11 C

q=2.8*10^-11 C

5 0
3 years ago
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Parking orbit is defined accurately by (a) 1" Kepler's law (b) 2 Kepler's law (c) 2 and 3 Kepler's law (d) 3" Kepler's law​
ehidna [41]

Answer:

hi iam 8 and a girl your hot

Explanation:

7 0
3 years ago
Two ice skaters collide on the ice. A 39.6-kg skater moving South at 6.21 m/s collides with a 52.1-kg skater moving East at 4.33
Stells [14]

Answer:

V = 3.6385 m/s

θ = 47.46 degrees

Explanation:

the important data in the question is:

Skater 1:

M_1= 39.6 kg

direction: south (axis y)

V_{1iy} = 6.21 m/s

Skater 2:

M_2 = 52.1 kg

direction: east (axis x)

V_{2ix} = 4.33 m/s

Now using the law of the conservation of linear momentum ( P_i = P_f and knowing that the collision is inelastic we can do the next equations:

M_{1}V_{1ix}+M_2V_{2ix} = V_{sx}(M_1+M_2)  (eq. 1)

M_{1}V_{1iy}+M_2V_{2iy} = V_{sy}(M_1+M_2)  (eq. 2)

Where V_{sx} and V_{sy} is the velocity of the sistem in x and y after the collision.

Note: the conservation of the linear momentum have to be make once by each axis.

Now, in the (eq. 1) the skater 1 don't have velocity in the axis x, so we can replace V_{1ix} by 0 in the equation and get:

M_2V_{2ix} = V_{sx}(M_1+M_2)  (eq. 1)

also, in the (eq. 2) the skater 2 don't have velocity in the axis y, so we can replace V_{2iy} by 0 in the equation and get:

M_{1}V_{1iy} = V_{sy}(M_1+M_2)  (eq. 2)

Now, we just replace the data in both equations:

(52.1)(4.33) = V_{sx}(39.6+52.1)  (eq. 1)

(39.6)(6.21) = V_{sy}(39.6+52.1)  (eq. 2)

solving for V_{sx] and V_{sy} we have:

V_{sx] = 2.46 m/s

V_{sy] = 2.681 m/s

using the pythagoras theorem we can find the magnitude of the velocity as:

V = \sqrt{2.46^2+2.681^2}

V = 3.6385 m/s

For find the direction we just need to do this;

θ = tan^{-1}(\frac{2.681}{1.46})

θ = 47.46 degrees

                     

 

3 0
3 years ago
For which of these questions could a testable hypothesis be developed? Check all that apply. A. Are gases better than solids? B.
Shalnov [3]

Testable hypotheses could be developed for questions  <em>B,  D,  and  E</em> .

The main problem with  A  and  C  is the word "better".  This is a rubber word.  It means different things to different people, and it can mean different things to the same person at different times.  It's always a matter of opinion, it has no unique units of measure, and there is no concrete way to measure it.  Not good for developing a testable hypothesis.

7 0
3 years ago
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Sounds are produced by vibrating objects a certain object, vibrates but a person nearby cannot hear any sound
d1i1m1o1n [39]
B.
The frequency of the vibration is above the normal human auditory range.

Normal audible range is from 20 hertz(cycles per second), to 20,000 Hz
As we age it is the higher frequencies we lose.
5 0
3 years ago
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