Answer:
6104 N/C.
Explanation:
Given:
k = 8.99 × 10^9 Nm2/C^2
Qx = 1.3 × 10^-5 C
rx = 7 m
Qy = 1 × 10−5 C
ry = 4 m
E = F/Q
= kQ/r^2
Ex = (8.99 × 10^9 × 1.3 × 10^−5) ÷ 7^2
= 2385.1 N/C.
Ey = (8.99 × 10^9 × 1.0 × 10^−5) ÷ 4^2
= 5618.75 N/C
Eo = sqrt(Ex^2 + Ey^2)
= sqrt(3.157 × 10^7 + 5.69 × 10^6)
= 6104 N/C.
Answer:
A. The period of an oscillation does not depend upon amplitude.
Explanation:
The period of a spring-mass system is:
T = 1/f = 2π√(m/k)
where f is the frequency, m is the mass, and k is the spring constant.
The answer isn't B. There are no frictionless systems in the real world.
The answer isn't C or D. As shown, the frequency is a function of both the mass and the spring constant.
The answer isn't E. Turning motion into heat is not an advantage for a clock.
The correct answer is A. The period of the system does not depend on the amplitude.
Answer: Option (c) is the correct answer.
Explanation:
When the child is tossed up into the air then she gains kinetic energy as the child has moved from its initial position.
It is given that mass is 20 kg, velocity is
, and height is 2 m.
Calculate the kinetic energy of child as follows.
kinetic energy = 
= 
= 
= 
Also, when child falls off the ground then she will have gravitational potential energy.
Calculate gravitational potential energy of child as follows.
Potential energy = m × g × h
= 
= 
False the correct answer is chemical bonds instead of thermal energy