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ale4655 [162]
3 years ago
8

What happens when a sound wave passes from oil into air? A. the sound wave slows down and bounces back B. the sound wave slows d

own and bends C. the sound wave speeds up and bounces back D. the sound wave speeds up and bends
Physics
1 answer:
Jlenok [28]3 years ago
6 0

Oil is optically denser than water. When sound/light goes from optically denser medium to optically rarer medium, their velocity increase and they moves away for normal.

<h3><u>Appropriate</u><u> </u><u>Answer</u><u>:</u></h3>

The sound wave speeds up and bends

\Large{ \underline{ \boxed{ \pink{ \bf{Option \: (D)}}}}}

As, In optics we learnt that light undergoes refraction when travels from medium of different densities. Similarly, Sound also follows the law of refraction.

  • It is due to the change of speed of water in different mediums, This makes it speed up or down depending upon the medium and their densities.

<u>━━━━━━━━━━━━━━━━━━━━</u>

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Consider a 2250-lb automobile clocked by law-enforcement radar at a speed of 85.5 mph (miles/hour). if the position of the car i
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As per law of Heisenberg uncertainty law

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When food is digested, the
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Chemical change

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The specific heat capacity of sea water is 4100 J/Kg°C and the boiling point of 100.6 °C. (i) Calculate the energy required to r
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Answer:

334.314 (kJ)

Explanation:

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6 0
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A horizontal force of magnitude 30.2 N pushes a block of mass 3.50 kg across a floor where the coefficient of kinetic friction i
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Answer:

A) 89.39 J

B) 30.39J

C) 23.8 J

Explanation:

We are given;

F = 30.2N

m = 3.5 kg

μ_k = 0.646

d = 2.96m

ΔEth (Block) = 35.2J

A) Work done by the applied force on the block-floor system is given as;

W = F•d

Thus, W = 30.2 x 2.96 = 89.39 J

B) Total thermal energy dissipated by the whole system which includes the floor and the block is given as;

ΔEth = μ_k•mgd

Thus, ΔEth = 0.646 x 3.5 x 9.8 x 2.96 = 65.59J

Now, we are given the thermal energy of the block which is ΔEth (Block) = 35.2J.

Thus,

ΔEth = ΔEth (Block) + ΔEth (floor)

Thus,

ΔEth (floor) = ΔEth - ΔEth (Block)

ΔEth (floor) = 65.59J - 35.2J = 30.39J

C) The total work done is considered as the sum of the thermal energy dissipated as heat and the kinetic energy of the block. Thus;

W = K + ΔEth

Therefore;

K = W - ΔEth

K = 89.39 - 65.59 = 23.8J

3 0
3 years ago
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