Given: distance 1 d₁ = 40 m; distance 2 d₂ = 3.8 m g = -9.8 m/s²
Initial Velocity Vi = 0 Final Velocity of stone 2 is unknown = ?
Total distance dₓ = d₁ - d₂ = 40 m - 3.8 m = 36.2 m
Formula: a = Vf² - Vi²/2d derive for Final Velocity Vf
acceleration is now due to gravity, therefore a = g
Vf = √2gd Vf = √2(9.8 m/s²)(36.2 m)
Vf = 26.64 m/s
Reason: The second stone will still start from rest.
<u>Weight = (mass) x (acceleration of gravity)</u>
Weight = 63 N
On Earth, acceleration of gravity = 9.8 meters per second².
63 N = (mass) x (9.8 meters per second²)
Divide each side of the equation by (9.8 m/s²).
63 / 9.8 = Mass
<em> Mass = 6.4 kilograms</em>
Answer:
A
Explanation:
option A is correct
the best example of elastic collision among the following is collision between two billiard balls. In collision of two billiard balls the energy lost is very little approximately zero. hence we can say that the kinetic energy is conserved. since, the kinetic energy is conserved we can say that the collision is elastic
