The age of the galaxy when we look back is 13.97 billion years.
The given parameters:
- <em>distance of the galaxy, x = 2,000 Mpc</em>
According Hubble's law the age of the universe is calculated as follows;
v = H₀x
where;
H₀ = 70 km/s/Mpc
![T = \frac{x}{V} \\\\T = \frac{x}{xH_0} \\\\T = \frac{1}{H_0} \\\\T = \frac{1}{70 \ km/s/Mpc} \\\\T = \frac{1 \ sec}{70 \times 3.24 \times 10^{-20} } \\\\T = 4.41 \times 10^{17} \ sec\\\\T = \frac{4.41 \times 10^{17} \ sec\ \times \ years}{3600 \ s \ \times\ 24\ h\ \times \ 365.25 \ days} \\\\T = 1.397 \times 10^{10} \ years\\\\T = 13.97 \ billion \ years](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7Bx%7D%7BV%7D%20%5C%5C%5C%5CT%20%3D%20%5Cfrac%7Bx%7D%7BxH_0%7D%20%5C%5C%5C%5CT%20%3D%20%5Cfrac%7B1%7D%7BH_0%7D%20%5C%5C%5C%5CT%20%3D%20%5Cfrac%7B1%7D%7B70%20%5C%20km%2Fs%2FMpc%7D%20%5C%5C%5C%5CT%20%3D%20%5Cfrac%7B1%20%5C%20sec%7D%7B70%20%5Ctimes%203.24%20%5Ctimes%2010%5E%7B-20%7D%20%7D%20%5C%5C%5C%5CT%20%3D%204.41%20%5Ctimes%2010%5E%7B17%7D%20%5C%20sec%5C%5C%5C%5CT%20%3D%20%5Cfrac%7B4.41%20%5Ctimes%2010%5E%7B17%7D%20%5C%20sec%5C%20%20%5Ctimes%20%5C%20years%7D%7B3600%20%5C%20s%20%5C%20%5Ctimes%5C%20%2024%5C%20h%5C%20%20%5Ctimes%20%5C%20365.25%20%5C%20days%7D%20%5C%5C%5C%5CT%20%3D%201.397%20%20%5Ctimes%2010%5E%7B10%7D%20%5C%20years%5C%5C%5C%5CT%20%3D%2013.97%20%5C%20billion%20%5C%20years)
Thus, the age of the galaxy when we look back is 13.97 billion years.
Learn more about Hubble's law here: brainly.com/question/19819028
find acceleration force divided by Mass
a=f/m
This contraption is a lot of fun, and you really should try it
some time.
The sound waves move from one can to the other one
by traveling through the string.
Answer:
The distance represents the difference of the first position and last position of the body.
Explanation:
For example, if y axis represents the position axis, and the first position is 3, second 9 we can see that the distance is a (positive) projection of one position into another. 9-3=6
Hope this helps.