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MatroZZZ [7]
4 years ago
9

If the ball increases from 1 m/s to 2 m/s, by how much would kinetic energy increase

Physics
1 answer:
Tems11 [23]4 years ago
7 0
1 m/s cause it’s going up one
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2. What mechanism would you use to safely capture emissions?
devlian [24]

Carbon capture is the safest way to capture emission.

<u>Explanation:</u>

Emission of green house gases is one of the most lurking threat above humans. So one of the best ways to reduce emission is to capture the gases like carbon di-oxide or carbon monoxide, nitrous oxide etc. So mostly, the carbon di-oxide gas which is produced as waste is captured using adsorption, absorption, chemical looping etc.

In this method, they are captured from high source points like cement factory etc and then stored in a secluded region. Thus, the adsorption of these gases and then storing them in secluded region is the best option for capturing emission.

5 0
3 years ago
Students are completing a lab in which they let a lab cart roll down a ramp. The students record the mass of the cart, the heigh
Dennis_Churaev [7]

Answer:

second column

Explanation:

5 0
3 years ago
A. What is the RMS speed of Helium atoms when the temperature of the Helium gas is 343.0 K? (Possibly useful constants: the atom
kkurt [141]

Answer:

(a) 1462.38 m/s

(b) 2068.13 m/s

Explanation:

(a)

The Kinetic energy of the atom can be given as:

K.E = (3/2)KT

where,

K = Boltzman's Constant = 1.38 x 10⁻²³ J/k

K.E = Kinetic Energy of atoms = 343 K

T = absolute temperature of atoms

The K.E is also given as:

K.E = (1/2)mv²

Comparing both equations:

(1/2)mv² = (3/2)KT

v² = 3KT/m

v = √[3KT/m]

where,

m = mass of Helium = (4 A.M.U)(1.66 X 10⁻²⁷ kg/ A.M.U) = 6.64 x 10⁻²⁷ kg

v = RMS Speed of Helium Atoms = ?

Therefore,

v = √[(3)(1.38 x 10⁻²³ J/K)(343 K)/(6.64 x 10⁻²⁷ kg)]

<u>v = 1462.38 m/s</u>

(b)

For double temperature:

T = 2 x 343 K = 686 K

all other data remains same:

v = √[(3)(1.38 x 10⁻²³ J/K)(686 K)/(6.64 x 10⁻²⁷ kg)]

<u>v = 2068.13 m/s</u>

8 0
3 years ago
How many moles of MgCl2 are there in 302 g of the compound?
lisov135 [29]

Answer:

‍♀️‍♀️‍♀️‍♀️sorrryyyyy

3 0
3 years ago
Read 2 more answers
To drive a typical car at 40 mph on a level road for one hour requires about 3.2 × 107 J of energy. Suppose we tried to store th
tatiyna

Answer:

9000RPM

Explanation:

"Angular velocity" is directly related to kinetic energy, that is, the Kinetic energy equation would allow an approximation to the resolution investigated in the problem.

The equation for KE is given by:

KE = \frac{1}{2} lw ^ 2

Now, starting from there towards the <em>Angular equation of kinetic energy</em>, the moment of inertia (i) is used instead of mass (m), and angular velocity (w) instead of linear velocity (V)

That's how we get

KE_{Angular} = \frac{1}{2} Iw^2

calculating the inertia for a solid cylindrical disk, of

m = 400kg

r = 1.2 / 2 = 0.6m

I_{disk} = \frac{1}{2} mr^2 = (0.5) (400) (0.6)^2 = 72 kgm^2

We understand that the total kinetic energy is 3.2 * 10 ^ 7J, like this:

3.2*10^7 = \frac{1}{2} Iw^2 = (0.5) (72) w^2 = 36w^2w^2 = 3.2*10^7 / 36 = 0.0888*10^7 = 88.8*10^4

w = 9.43*10^2 = 943 rad / s

Thus,

943 rad / s ≈ 9000 rpm

6 0
3 years ago
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