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Agata [3.3K]
3 years ago
7

A car increases its speed from 20km/hr to 50km/hr in seconds. Its acceleration is _____.

Physics
1 answer:
mash [69]3 years ago
7 0

Answer:

Option D

0.83 m/s2

Explanation:

Time is assumed as 10 seconds

First, convert the speeds from km/h to m/s

20 km/h\times \frac {1000 m}{3600 s}=5.555555556 m/s \approx 5.56 m/s

50 km/h\times \frac {1000 m}{3600 s}=13.88888889  m/s \approx 13.89 m/s

Acceleration, a=\frac {v-u}{t} where u and v are the initial and final velocities respectively, t is the time taken to accelerate.

Substituting 13.89 m/s for v, 5.56 m/s for u and 10 s for t then

a=\frac {13.89-5.56}{10}=0.8333333 m/s^{2}\approx 0.83 m/s^{2}

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11. Hans and Frans are two workers being considered for a job at the UPS loading dock. Hans boasts that he can lift a 100 kg box
Marta_Voda [28]

Answer:

Hans is more powerful

Explanation:

Power: This can be defined as the rate at which work is done or energy is used up.

The expression for power is given as,

P = E/t

P = mgh/t................. Equation 1

Where P = power, W = Work, t = time, m = mass, h = height, g = acceleration due to gravity.

Hans' power

P = mgh/t

Given: m = 100 kg, h = 2 m, g = 9.8 m/s², t = 3 s

Substitute into equation 1

P = 100(9.8)(2)/3

P = 653.33 W.

Frans' power

P' = mgh/t

Given; m = 200 kg, h = 5 m, t = 20 s.

P' = 200(5)(9.8)/20

P' = 9800/20

P' = 490 W

from the above,

since P>P'

Hence, Hans is more powerful

8 0
3 years ago
A 56.0kg ice skater spins about a vertical axis through her body with her arms horizontally outstretched, making 2.50 turns each
Arada [10]

Answer:

Net force = 129.4, Force as multiple of weight of her hand = 18.84

Explanation:

Given Data:

Total body weight = 56.0 kg   ;

no. of turns = 2.5/second        ;

hand to hand distance = 1.5m ;

weight of hand = 1.25% of body weight ;

Solution:

mass of hand = \frac{1.25}{100}*56 = 0.7kg ;

radius = d/2 = 1.5/2 = 0.75m     ;

Now we need to find velocity, as we know that velocity can be calculated by dividing distance by time

v = d/t = \frac{2.5*2*3.14*0.75}{1} = 11.775 m/s or 12 m/s;

a.

The formula to calculate force is given as

F = mv²/r = (0.7*11.775²)/0.75 = 129.4 N

b.

To calculate force as multiple of weight on her hand, we need to calculate the gravitational force W on her hand first.

W = gm = 9.81 * 0.7 = 6.867 N

Now the wieght on her hand can be represented by

\frac{Force_{net} }{weight of hand}  = 129.4 / 6.867 = 18.84

3 0
3 years ago
As the temperature of an object increases, the wavelength of the brightest light emitted _______
alexira [117]

Answer:

option (B) decreases

Explanation:

According to the Wein's displacement law, the minimum wavelength of the radiated emission is inversely proportional to the absolute temperature of the body which emits radiation.

\lambda_{m}\alpha \frac{1}{T}

Where, T is the absolute temperature of the body and λm is the minimum wavelength of heat radiated.

Here, as the temperature increases, the wavelength decreases.

4 0
3 years ago
Three +3.0-μC point charges are at the three corners of a square of side 0.50 m. The last corner is occupied by a −3.0-μC charge
kramer

Answer:

E = 440816.32 N/C

Explanation:

Given data:

Three point charge of charge equal to +3.0 micro coulomb

fourth point charge = - 3.0 micro coulomb

side of square = 0.50 m

K =1/4 \pi \epsilon_0 = 8.99 \times 10^9 N.m^2/c^2

Due to having equal charge on center of square, 2 charge produce equal electric field at center and other two also produce electric field at center of same value

So we have

E_1 + E_3 = 0

E =E_2 + E_4

E = 2 E_2

[E_2 =\frac{2\times k \times q}{r^2}

[r= \frac{(0.5^2 + 0.5^2)^2}{2} = 0.35 m]

plugging all value

E = 2 E_2

E = 2 E_2 =\frac{2\times k \times q}{r^2}

E = \frac{2 \times 8.99 \times 10^93\times 10^{-6}}{0.35^2}

E = 440816.32 N/C

3 0
2 years ago
Read 2 more answers
A factory has 1200 workers of which 720 are male and the rast are female what percent of workers are female​
umka21 [38]

Answer:

Percent of Female Workers = 40%

Explanation:

The percentage of the female workers in the given group of workers can be easily found by the following formula:

Percent\ of\ Female\ Workers = \frac{No.\ of\ Female\ Workers}{Total\ No.\ of\ Workers}\ x\ 100\%

where,

Total No. of Workers = 1200

No. of Female Workers = Total Workers - No. of Male Workers

No. of Female Workers = 1200 - 720 = 480

Therefore,

Percent\ of\ Female\ Workers = \frac{480}{1200}\ x\ 100\%

<u>Percent of Female Workers = 40%</u>

7 0
2 years ago
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