Question

A certain car is capable of accelerating at a rate of 0.60 m/s^2. How long does it take for this car to go from a speed of 55mi/h to a speed of 60 mi/h?
I know the answer is 3.7seconds! I am just confused on the steps to get the answer.

Answer 1

 Final velocity = Initial velocity – 9.8 * t
Final velocity = 80.5 – 9.8 * 0.0124 = 80.378 m/s
OR
Final velocity = 80.5 – 9.8 * 16.416 = 80.378 m/s

A. -32 m/s
B. -97 m/s
C. -64 m/s
D. -81 m/s
E. -48 m/s

Answer 2

This car needs 3.7 seconds to go from a speed of 55 mi/h to a speed of 60 mi/h.

Further explanation

Acceleration is rate of change of velocity.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem !

Given:

Acceleration = a = 0.60 m/s²

Initial Velocity = u = 55 mi/h = 24,5872 m/s

Final Velocity = v = 60 mi/h = 26,8224 m/s

Unknown:

Time Taken = t = ?

Solution:

Recall the formula for calculating acceleration as mentioned above.

$a = \frac{v - u }{t}$

$t = \frac{v - u }{a}$

$t = \frac{26.8224 - 24.5872}{0.6}$

$t = \frac{2.2352}{0.6}$

$t \approx 3.7 ~ seconds$

Learn more

• Velocity of Runner : brainly.com/question/3813437
• Kinetic Energy : brainly.com/question/692781
• Acceleration : brainly.com/question/2283922
• The Speed of Car : brainly.com/question/568302

Answer details

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate