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sergiy2304 [10]

3 years ago

11

what car experiences more impulse - one stopped by a wood block fixed in place, or one stopped by a foam noodle that is allowed

to move?

1 answer:

forsale [732]3 years ago

4 0

What do you mean with this question?

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What is the wavelength of the radio waves from an FM station operating at a frequency of 99.5 MHz

ser-zykov [4K]

Answer:

Wavelength, $\lambda=3.01\ m$

Explanation:

It is given that,

Frequency, f = 99.5 MHz = 99.5 × 10⁶ Hz

We need to find the wavelength of the radio waves from an FM station operating at above frequency. The relationship between the frequency and the wavelength is given by :

$c=f\lambda$

$\lambda=\dfrac{c}{f}{$

c = speed of light

$\lambda=\dfrac{3\times 10^8\ m/s}{99.5\times 10^6\ Hz}$

$\lambda=3.01\ m$

So, the wavelength of the radio waves from an FM station is 3.01 m. Hence, this is the required solution.

3 0

4 years ago

Explain why, if you go to the moon, your weight would change but your mass wouldnt

Evgen [1.6K]

There's little gravity so your weight would change but not your mass

3 0

3 years ago

Star temperature is indicated by?

astraxan [27]

A star's temperature is most likely indicated by the color of it. The hotter the star, the bluer it is. The colder the star, the redder it is.

3 0

4 years ago

Based on the velocity-time graph given, the acceleration of the object is..

fredd [130]

It’s gonna have to b since it’s decreasing

4 0

3 years ago

A professional racecar driver buys a car that can accelerate at 5.9 m/s2. The racer decides to race against another driver in a

3241004551 [841]

Answer:

(a) Time will be t = 3.56 sec

(b) Distance traveled by car when they are side by side is 37.38712 m

(b) Velocity of race car = 21.004 m/sec

velocity of stock car = 12.816 m/sec

Explanation:

We have given acceleration of the car $a_1=5.9m/sec^2$

Acceleration of the stock car $a_2=3.6m/sec^2$

When 1st car overtakes the second car then distance traveled by both the car will be same

(a) So $s_1=s_2$

As both car starts from rest so initial velocity of both car will be 0 m/sec

It is given that stock car leaves 1 sec before

So $\frac{1}{2}\times 5.9\times t^2=\frac{1}{2}\times (t+1)^2\times 3.6$

After solving t = 3.56 sec

(b) From second equation of motion $s=ut+\frac{1}{2}at^2=0\times 3.56+\frac{1}{2}\times 5.9\times 3.56^2=37.38712m$

(c) From first equation pf motion v = u+at

So velocity of race car v = 0+5.9×3.56 = 21.004 m/sec

Velocity of stock car v = 0+ 3.6×3.56 = 12.816 m/sec

3 0

3 years ago