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sergiy2304 [10]

3 years ago

11

what car experiences more impulse - one stopped by a wood block fixed in place, or one stopped by a foam noodle that is allowed

to move?

1 answer:

forsale [732]3 years ago

4 0

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An object is dropped from a platform 100 feet high. Ignoring wind resistance, what will its speed be when it reaches the ground?

ICE Princess25 [194]

<span>if we assume the origin is at the dropping point and the object is merely dropped and not thrown up or down then y0 = 0 and v0 = 0. The equation reduces to </span>

<span>y = 0 + 0t + ½gt² </span>
<span>y = ½gt² </span>

<span>t = √(2y/g) </span>

<span>in the ft - lb - s system </span>

<span>y = -100 ft </span>
<span>g = -32.2 ft / s² </span>

<span>t = √(2y/g) </span>
<span>t = √(2(-100) / (-32.2)) </span>
<span>t = 2.5 s</span>

7 0

4 years ago

Read 2 more answers

A pitcher exerts a force on a baseball that is 30 times the balls weight. How fast is the pitcher accelerating the ball?

iVinArrow [24]

Answer:

Pitcher is accelerating the ball at 30 times of acceleration due to gravity = 294 m/s²

Explanation:

Force applied on baseball = 30 times weight of the ball.

Weight of ball = mg, where m is the mass of ball and g is acceleration due to gravity value.

We have force applied is also equal to product of mass and acceleration.

F = ma = 30 x mg

a = 30g

So, pitcher is accelerating the ball at 30 times of acceleration due to gravity = 294 m/s²

8 0

4 years ago

Choose all that apply. Solids, liquids, and gases can be distinguished by their:

vodomira [7]

I believe its by there shape

8 0

3 years ago

Read 2 more answers

Katelyn (55 kg) is practicing a drop jump in the biomechanics lab. She steps off a plyometrics box, lands on the force plate, an

suter [353]

Answer:

J = 357.5 kg*m/s

Explanation:

The impulse exerted on Katelyn when she was on the force plate, is equal to the change in her momentum, according to Newton's 2nd Law.
Assuming as the positive direction the upward direction (coincident with the positive y-axis) we can express the initial momentum as follows:

$p_{o} = m*v_{o} = 55 kg * (-3.0 m/s) (1)$

By the same token, the final momentum is as follows:

$p_{f} = m*v_{f} = 55 kg * (3.5 m/s) (2)$

As we have already said, the impulse J is just equal to the change in momentum, i.e., the difference between (2) and (1):

$J = p_{f} - p_{o} = m* (v_{f} -v_{o}) = 55 kg* (3.5m/s- (-3.0m/s)) = 357.5 kg*m/s (3)$

5 0

3 years ago

What's 600,000,000 divided by 3,000.000,000,000?

Murljashka [212]

Answer:0.000002

Explanation: I Looked It Up lol

5 0

3 years ago