Answer:
A. Oxidation refers to loss of electron or increase in oxidation state. Reduction refers to gain of electrons or decrease in oxidation state.
B. The oxidation number of S in S₂O₃²⁻ is +2.
C. The oxidation number of S in S₄O₆²⁻ is +5/2.
Explanation:
A. Oxidation refers to loss of electron or increase in oxidation state. Reduction refers to gain of electrons or decrease in oxidation state.
The overall charge on a molecule is equal to the sum of the oxidation states of all the atoms in a molecule.
B. S₂O₃²⁻ : The oxidation state of oxygen (O) is -2 and overall charge on molecule is -2.
Therefore, the oxidation state of sulfur (x) can be calculated by
2x + 3 (-2) = -2
2x + (-6) = -2
2x = -2 + 6 = 4
x = 4 ÷ 2= +2
<u>Therefore, the oxidation number of S is +2.</u>
C. S₄O₆²⁻ : The oxidation state of oxygen (O) is -2 and overall charge on molecule is -2.
Therefore, the oxidation state of sulfur (x) can be calculated by
4x + 6 (-2) = -2
4x + (-12) = -2
4x = -2 + 12 = 10
x = 10 ÷ 4 = +5/2
<u>Therefore, the oxidation number of S is +5/2.</u>
PH is the potential of hydrogen, pH provides a measure of the concentration of hydrogen ion while pOH scale provides the concentration of OH- ions.
pH denotes the negative logarithm of concentration of hydrogen while pOH denotes the negative logarithm of the concentration OH- ions.
Therefore; in this case the pOH= -log (OH-)
= - log (10^-10)
= 10
If the pOH is 10 then the pH of the solution will be 4
Recall that a mole is defined as Avogadros number of particles.
What the formula of caffeine basically tells us is that for every molecule of caffeine, you will have 4 atoms of nitrogen
So, if we have 0.3 moles of caffeine we will have 4*0.3 moles of nitrogen which is 0.12.
And you got the idea
Cheers
I THINK this is the answer: 4809.35999999786. (found it on a website)
You would be billion years old