Answer:
Condenses at 27.25K.
Freezes at 24.65K.
Explanation:
In order to solve this above question, there is is need to make use of the following equation. The main idea here is to convert degree celsius to Kelvin. Hence,
0°C + 273.15 = 273.15K---------------------(1).
Therefore, we will make use of the above equation (1) and slot in the values for at degree celsius at which it condenses and at degree celsius at which it freezes.
So, we have at temperature at which it condenses:
-245.9°C + 273.15 = 27.25K.
Also, we have at temperature at which it freezes.
-248.5°C + 273.15 = 24.65K.
It absorbs heat and give off thermal energy just saying i think its right
Other group because they weren’t in the right group
The electronic configuration for vanadium (V) in the periodic table is as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3 (option D).
<h3>What is electronic configuration?</h3>
Electronic configuration is the the arrangement of electrons in an atom, molecule, or other physical structure like a crystal.
Vanadium is the 23rd element on the periodic table and has chemical symbol V with atomic number 23. It is a transition metal, used in the production of special steels.
This suggests that the electronic configuration of Vanadium will be written as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3
Therefore, the electronic configuration for vanadium (V) in the periodic table is as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3.
Learn more about electronic configuration at: brainly.com/question/14283892
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1 CH4 (g) + 2 O2 (g) -----> CO2 (g) + 2H2O(l) ΔH= - 890 kJ
1 mol 2 mol
1) If ΔH has minus, it means "release". We need only "release" choices.<span>
2) From reaction
1 mol </span>CH4 (g) "releases" ΔH= - 890 kJ - We do not have this choice.
2 mol O2 (g) "release" ΔH= - 890 kJ, so
1 mol O2 (g) "release" ΔH= - 445 kJ
Correct answer is B.