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Luba_88 [7]
3 years ago
7

What is the difference between a purine and a pyrimidine?

Chemistry
1 answer:
GalinKa [24]3 years ago
4 0

Answer: Adenine and guanine are the two purines and cytosine, thymine and uracil are the three pyrimidines. The main difference between purines and pyrimidines is that purines contain a sixmembered nitrogencontaining ring fused to an imidazole ring whereas pyrimidines contain only a sixmembered nitrogencontaining ring. They both are types or categories of nitrogen containing bases present in nuclei acids of DNA and RNA.

Purines are 2 Ring or Carbon Ring, Nitrogen containing bases. That consist of these 2 rings next placed next to each other. These examples include - Adenine and Guanine.

Pyrimidines are 1 or single Ring Nitrogen containing structures. There are 3 nitrogenous bases that are categorized as pyrimidines. Cytosine, Thymine, and Uracil.

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The upper part of the mantle is <br> Hard<br> OR<br> Soft
sladkih [1.3K]

Answer: Hard

Explanation:

The upper part of the mantle is hard as it contains thick rock layers. The mantle's upper layer and the crust make up a brittle and rigid rock that's referred to as the Lithosphere.

The upper mantle starts below the Earth crust and then stops at the start of the lower mantle. We should note that the upper mantle results in the movement of the tectonic plates.

6 0
3 years ago
Does a dead tree count as biotic or abiotic?
Ganezh [65]
Abiotic
is the answer for you
8 0
3 years ago
Read 2 more answers
Many classic experiments have given us indirect evidence of the nature of the atom. Which of the experiments listed below did no
belka [17]

Answer:

The experiment that did not give the results described is e) The Rutherford experiment proved the Thomson "plum-pudding" model of the atom to be essentially correct.

Explanation:

  1. First of all, let's start with the experiment listed in <em>b) The Rutherford experiment was useful in determining the nuclear charge on the atom</em>. This is true, because Rutherford was able to tell through this experiment that the atoms consisted mostly of empty space, with a positively charged nucleus in its center (he was able to tell it was positive because of the deflections observed on the positive alpha particles he used).
  2. Next, we have experiment <em>c) The electric discharge tube proved that electrons have a negative charge</em>. This is also true, given that Thomson was able to correctly determine that there existed particles that were negatively charged, called electrons (he determined this by observing that the rays deviated from the negatively charged plate of the discharge tube in his experiment).
  3. Experiment d) <em>Milikan's oil-drop experiment showed that the charge on any particle was a simple multiple of the charge on the electron</em>, also states the correct results. He was able to determine the charge of many electrically charged droplets of oil, and found out that the charges were a simple multiple of a base value, which he proposed to be that of the negative charge of an electron.
  4. Finally, we take a look at experiment <em>e) The Rutherford experiment proved the Thomson "plum-pudding" model of the atom to be essentially correct</em>. This is the experiment that did not give the result described. In fact, the Rutherford experiment proved that Thomson's "plum-pudding" model was not correct. This is because he determined that atoms consist mostly of empty space, with a dense, positively charged nucleus in its center, surrounded by negatively charged electrons. If Thomson's model were true, Rutherford would have not observed deflected alpha particles in his experiment.
8 0
3 years ago
Heat is being removed from a substance, but its temperature does not change. What is
ololo11 [35]
So its temperature will not rise, since kinetic energy of molecules remains the same. The quantity of heat absorbed or released when a substance changes its physical phase at constant temperature (e g. From solid to liquid at melting point or from liquid to gas at boiling point) is termed as its latent heat.
4 0
2 years ago
The specific heat capacity of a certain type of cooking oil is 1.75 J/(g⋅∘C). What is the amount of heat exchanged when the temp
anygoal [31]

Answer:

Q = -811440 J

Explanation:

Given data:

Mass of oil = 2.76 Kg (2.76× 1000 = 2760 g)

Initial temperature = 191 °C

Final temperature = 23°C

Specific heat capacity of oil = 1.75 J/g.°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 23°C - 191 °C

ΔT = -168°C

Q = 2760 g ×1.75 J/g.°C  ×-168°C

Q = -811440 J

Negative sign show heat is released.

6 0
3 years ago
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