A. Define the terms 'oxidation' and 'reduction.
1 answer:
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The molecular formula : As₄S₆
<h3>Further explanation</h3>Given
Rate of effusion of arsenic(III) sulfide = 0.28 times the rate of effusion of Ar atoms
Required
The molecular formula
Solution
Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or
the effusion rates of two gases = the square root of the inverse of their molar masses:
or
Input the value :
1 = Arsenic(III) sulfide
2 = Ar
MM Ar = 40 g/mol
0.28 = √(40/M₁)
M₁=40 : 0.28²
M₁=510 g/mol
The empirical formula of arsenic(III) sulfide = As₂S₃
(Empirical formula)n = molecular formula
( As₂S₃)n = 510 g/mol
(246.02 g/mol)n = 510 g/mol
n = 2
So the molecular formula : As₄S₆
Mass of chlorine = (given)
Molar mass of chlorine =
Now, number of moles is defined as the ratio of given mass in gram to the molar mass of the compound.
Number of moles =
Number of moles of chlorine =
=
Now, according to significant figure rules, the least number of significant figure in the question identifies the number of significant figures in the solution.
Thus, in question, both digit have four significant figures, therefore, the answer must be in four significant figures.
Hence, number of moles of chlorine =