Answer: -3, -5, -7 from top to bottom
Step-by-step explanation:
just plug in the x to the function f(x)=-x
which mean f(x)=-3, f(x)=-5, f(x)=-7
The ratios that are equivalent to 5/20ths, are 1/4th and 25/100ths.
Go ahead and do your own work buddy that’s how you learn shisjdjdhdifndkdnebe
To solve this problem you must apply the proccedure shown below:
1. You must use the formula for calculate the surface area and the volume of the tank:
2. Solve for 
in the second equation and substitute it into the first one.Then, you have:
3. Now, derivate:
4. When you solve for 
, you obtain:
![2x^{3}-256=0\\ x=\sqrt[3]{\frac{256}{2}} \\ x=5.03](https://tex.z-dn.net/?f=%202x%5E%7B3%7D-256%3D0%5C%5C%20x%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B256%7D%7B2%7D%7D%20%20%5C%5C%20x%3D5.03%20)
5. Now, you must calculate :
Therefore, the dimensions are:
The sides of the base of the tank: 
The height of the tank: 
<h2>Answer:</h2>
8.75 feet
<h2>
Step by step:</h2>
Given that a 12 foot ladder leans against a building seven feet above the ground.
By using trigonometry ratio, the angle between the ladder and the ground will be
SinØ = opposite/ hypothenus
SinØ = 7 / 12
SinØ = 0.58333
Ø = Sin^-1(0.58333)
Ø = 35.69 degree
At what height would an 15 foot ladder touch the building if both ladders form the same angle with the ground?
Using the same trigonometric ratios
SinØ = opposite/hypothenus
Sin 35.69 = opposite/ 15
Cross multiply
Opposite = 15 × sin 35.69
Opposite = 8.75 feet
Therefore, the ladder will touch the building if both ladders form the same angle with the ground at height 8.75 feet.
