Scotts has a jar of quarters and dimes if there is $4.15 in the jar and there is 4 dimes how many quarters are in the jar

A parabola has a line of symmetry x = -5. The minimum value of the quadratic function that it represents is -7. Find a possible

Ilya [14]

hello :
the parabola's equation is : f(x) = a(x-h)²+k
the verex is (h,k)
line of symmetry x = h
The minimum or maximum value is : k
a possible equation of this parabola is : f(x) = a(x+5)²-7

6 0

3 years ago

Choose the Athat seems to be congruent to the given one.

julia-pushkina [17]

Answer:

a. ∆EGF ≅ ∆EGD

Step-by-step explanation:

Congruent triangles would have the same side lengths and the same measure of angles.

From the figure given:

EG in ∆EGF ≅ EG in ∆EGD

GF in ∆EGF ≅ GD in ∆EGD, also

EF ≅ ED.

The three angles in ∆EFG are also congruent to the three angles in ∆EGD.

Therefore, ∆EGD is congruent to ∆EGF.

∆EGF ≅ ∆EGD

7 0

3 years ago

Tell whether the lines through the given points are parallel, perpendicular, or neither.

antoniya [11.8K]

Answer:

The Slope of Line 1 is -> $-\frac{2}{9}$

The Slope of Line 2 is -> $-\frac{9}{2}$

These two lines are - > Perpendicular

Step-by-step explanation:

To find the slope of line one, you follow these steps:

First Coordinate 10 -> x1, 5 -> y1

Second Coordinate -8 -> x2, 9 -> y2

Then insert the assigned values into this equation: $\frac{y2-y1}{x2-x1}$ -> $\frac{9-5}{-8-10}$ which equals $\frac{4}{-18}$ which simplifies to $-\frac{2}{9}$

Then do the same process to find the slop of line 2:

First Coord: 2 -> x1, -4 -> y1

Second Coord: 11 -> x2, -6 -> y2

Then insert the values into this equation: $\frac{y2-y1}{x2-x1}$ -> $\frac{11-2}{-6-(-4)}$ which equals $\frac{9}{-2}$ .

We know the lines are perpendicular by:

a. Typing the equations of the lines into a graphing calculator and observing the graph

b. Looking at the slopes. By looking at the slopes, we see that the slope of line 1 is the reciprocal of line 2, and vice versa. Since reciprocal slopes indicate perpendicular lines, the lines 1 and 2 are perpendicular to each other.

Hope this helps!

5 0

3 years ago

The diagram shows the diffrence between my home h and two towns

katrin2010 [14]

Answer:

from home to town A :

V = D/t = 10 / 20 = 0.5 mile per min

from home to town B :

V = D/t = 20/30 = (2/3) mile per min

From town A to town B :

V = D/t = (10+20)/ 50 = (3/5) mile per min

6 0

3 years ago

Read 2 more answers

Please help solve for x..

aalyn [17]

Answer:

x = 1 or x = -1

Step-by-step explanation:

Given equation:

$x^{100}-4^x \cdot x^{98}-x^2+4^x=0$

Factor out -1:

$\implies -1(-x^{100}+4^x \cdot x^{98}+x^2-4^x)=0$

Divide both sides by -1:

$\implies -x^{100}+4^x \cdot x^{98}+x^2-4^x=0$

Rearrange the terms:

$\implies 4^x \cdot x^{98}-4^x-x^{100}+x^2=0$

$\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c \quad \textsf{to }x^{100}:$

$\implies 4^x \cdot x^{98}-4^x-x^{98}x^2+x^2=0$

Factor the first two terms and the last two terms separately:

$\implies 4^x(x^{98}-1)-x^2(x^{98}-1)=0$

Factor out the common term $(x^{98}-1)$ :

$\implies (4^x-x^2)(x^{98}-1)=0$

Zero Product Property: If a ⋅ b = 0 then either a = 0 or b = 0 (or both).

Using the Zero Product Property, set each factor equal to zero and solve for x (if possible):

$\begin{aligned}x^{98}-1 & = 0 & \quad \textsf{or} \quad \quad4^x-x^2 & = 0 \\x^{98} & =1 & 4^x & = x^2 \\x & = 1, -1 & \textsf{no}& \textsf{ solutions for } x \in \mathbb{R}\end{aligned}$

Therefore, the solutions to the given equation are: x = 1 or x = -1

Learn more here:

brainly.com/question/27751281

brainly.com/question/21186424

3 0

1 year ago