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Mariulka [41]
4 years ago
14

Scotts has a jar of quarters and dimes if there is $4.15 in the jar and there is 4 dimes how many quarters are in the jar

Mathematics
1 answer:
ch4aika [34]4 years ago
3 0
4 dimes is $.40

$4.15 - $.40 = $3.75

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the sum of three consecutive numbers is 41 less than five times the largest number. find the largest number
ivann1987 [24]
Hi,

You can write your problem as an equation.

x - 2 + x - 1 + x = 5x - 41 ,

x being the largest number.
So,

3x - 3 = 5x - 41
3x - 5x = -41 +3
-2x = -38
2x = 38
x = 38/2 = 19

The largest number is 19.

Hope this helps! If my answer was not clear enough or you’d like further explanation please let me know. Also, English is not my first language, so I’m sorry for any mistakes.
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4 years ago
Find the slope and y-intercept of the line in each graph. (Explore Activity 1) Please help me
Anit [1.1K]

Answer:

1. Slope = -2 , y-intercept = 1

2. Slope = 5 , y-intercept = -15

3. Slope = 1.5 , y-intercept = -2

4. Slope = -3 , y-intercept = 9

Step-by-step explanation:

1. The slope is -2 because using the formula y₁-y₂÷x₁-x₂ you can use the points given to you to get -2. It doesn't matter which one you pick as y1 or y2, just make sure you keep it consistent with the x numberings. I did 1--3 (which becomes 1+3) and 0-2. Those equal 4/-2 which gives you -2. Use these same steps for all of them, but with ones that don't have the points given, just pick two that are whole numbers and not decimals. For finding the y-intercept, just find the point that is on the y axis line. It is given on number one as (0,1). So, the y-intercept is 1. Hope this helps!

6 0
3 years ago
A university dean of students wishes to estimate the average number of hours students spend doing homework per week. The standar
Ad libitum [116K]

Answer:

The Sample Size Need To be at least 114

Step-by-step explanation:

According to the Question,

  • Given, A university dean of students wishes to estimate the average number of hours students spend doing homework per week. The standard deviation from a previous study is 6.2 hours.

The Maximum Error(E) is given as 1.5 hours and the standard deviation(σ) is 6.2 hours.

  • Now, For 99% Confident the level of value α is 0.01.

α/2 = 0.01/2 ⇒ 0.005

  • Thus, From The table, We get that the value of Z_{alpha/2} is 2.58.

Hence, the sample size n can be found as

n = {\frac{(Z_{alpha/2} * Standard Deviation)}{E}}²

n = {2.58 × 6.2}² / 1.5²

n = 113.72 .

So, The Sample Size Need To be at least 114.

4 0
3 years ago
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