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3 years ago

Select all that apply.

Physics

2 answers:

ikadub [295]3 years ago

6 0

All are true except the first two.

kolbaska11 [484]3 years ago

6 0

Positively charged objects attract negatively charged objects.

-PlushDna

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If a shuttle is orbiting a planet at a distance of 40 miles from the center of the planet, and is traveling at a rate of 500 mil

lawyer [7]

Answer:

Time taken, t = 30.15 minutes

Explanation:

It is given that,

Distance from the center of planet, r = 40 miles

Speed of the shuttle, v = 500 miles per hour

Let t is the time taken by it to complete one full orbit. The displacement of the shuttle is,

$d=2\pi r$

$d=2\pi \times 40$

d = 251.32 miles

Now time can be calculated using the expression for the velocity as :

$v=\dfrac{d}{t}$

$t=\dfrac{d}{v}$

$t=\dfrac{251.32\ miles}{500\ miles\ per\ hour}$

t = 0.50264 hours

t = 30.15 minutes

So, the shuttle will take 30.15 minutes to complete one full orbit. Hence, this is the required solution.

7 0

3 years ago

- An impulse is equivalent to

Alik [6]

Answer:

Explanation:

impulse Is the product of force and distance so it's generally formula

5 0

3 years ago

A soccer player sprinting down the field demonstrates which form of energy?

Likurg_2 [28]

Answer:

kinetic energy

Explanation:

Kinetic energy is energy in motion

6 0

3 years ago

Read 2 more answers

List down the different phases of the Moon

mixas84 [53]

Answer:

new Moon.

waxing crescent Moon.

first quarter Moon.

waxing gibbous Moon.

full Moon.

waning gibbous Moon.

last quarter Moon.

waning crescent Moon.

Explanation:

7 0

3 years ago

Read 2 more answers

The amount of power required to move an object can be increased without changing the

VLD [36.1K]

Answer:

Yes it is possible to increase the power with out changing the amount of work.

Explanation:

The power is defined by the amount of power divided by the time. This time is the one needed to do the work. We can understand this issue by analyzing an example with numeric values.

Work = 500 [J]

Time = 5 [s]

Power will be:

$Power=\frac{500}{5} \\Power=100 []watt]\\$

Now if we change the time to 2 seconds:

$Power = 500 [J]/2[s]\\Power = 250 [watt]\\$

As we can see, the power was increased without the need to change the work.

3 0

4 years ago