The answer is: [C]: "protons and electrons" .
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Answer:1/4 the brightness of star b
Explanation:
Answer:
(a) 1.21 m/s
(b) 2303.33 J, 152.27 J
Explanation:
m1 = 95 kg, u1 = - 3.750 m/s, m2 = 113 kg, u2 = 5.38 m/s
(a) Let their velocity after striking is v.
By use of conservation of momentum
Momentum before collision = momentum after collision
m1 x u1 + m2 x u2 = (m1 + m2) x v
- 95 x 3.75 + 113 x 5.38 = (95 + 113) x v
v = ( - 356.25 + 607.94) / 208 = 1.21 m /s
(b) Kinetic energy before collision = 1/2 m1 x u1^2 + 1/2 m2 x u2^2
= 0.5 ( 95 x 3.750 x 3.750 + 113 x 5.38 x 5.38)
= 0.5 (1335.94 + 3270.7) = 2303.33 J
Kinetic energy after collision = 1/2 (m1 + m2) v^2
= 0.5 (95 + 113) x 1.21 x 1.21 = 152.27 J
Answer:
The male gamete is smaller in comparison to that of the female gamete.
The male gamete is conical from the front while the female gamete is spherical.
The cytoplasm in the male gamete is less in comparison to that of the female gamete.
The male gamete can move with the help of the tail while the female gametes are immobile and do not have any tail or flagella present.
The number of mitochondria present in the sperm is less than the number of mitochondria present in the ovum.
The male gamete has acrosome present in the head region that contains enzymes for dissolving the membranes present around the ovum. The ovum does not contain such digestive enzymes.
Explanation:
For this case we have that by definition, the kinetic energy is given by the following formula:
Where:
m: It is the mass
v: It is the velocity
According to the data we have to:
Substituting the values we have:
finally, the kinetic energy is 
Answer:
Option A
