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tiny-mole [99]
3 years ago
14

An airplane is flying in a horizontal circle at a speed of 100 m/s. The 80.0 kg pilot does not want the centripetal acceleration

to exceed 7.00 times free-fall acceleration.
Physics
1 answer:
Tema [17]3 years ago
3 0

Answer:

The force will be "5,488". A further solution is provided below.

Explanation:

The given values are:

speed,

v = 100m/s

mass,

m = 80 kg

acceleration,

a = 7

Now,

Radius will be:

⇒ r=\frac{v^2}{ac}

⇒    =\frac{(100)^2}{7\times 9.8}

⇒    =\frac{10000}{68.6}

⇒    =145.77

Force will be:

⇒ F=m\times ac

⇒     =80\times 68.6

⇒     =5488

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Answer:

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A redecor travelling of 94 m/s s lows at a anstant
kotykmax [81]

Answer:

638 m.

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 94 m/s

Final velocity (v) = 22 m/s

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We can obtain the distance travelled by using the following formula:

s = (u + v) t /2

s = (94 + 22) × 11 /2

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3 0
3 years ago
a girl performed 50j of work lifting a heavy box it took her 5 seconds to lift the box what is her power
son4ous [18]

Answer:

10 W

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3 0
3 years ago
The main water line enters a house on the first floor. The line has a gauge pressure of 2.10 x 105 Pa. (a) A faucet on the secon
Eva8 [605]

To answer this question is necessary to apply the concepts related to Bernoulli's equation. The Bernoulli-related concept describes the behavior of a liquid moving along a streamline. Pressure can be defined as the proportional ratio between height, density and gravity:

P = h\rho g

Where,

h = Height

\rho = Density

g = Gravity

Our values are

\rho = 1000kg/m^3 \rightarow density of water at normal conditions

h = 7.3m

g = 9.8m/s^2

PART A) Replacing these values to find the total pressure difference we have to

P_1 = h_1 \rho g

P_1 = (7.3)(1000)(9.8)

P_1 = 71540Pa

In this way the pressure change would be subject to

\Delta = P_2-P_1

\Delta = 2.1*10^5Pa- 0.7154*10^5Pa

\Delta = 138460Pa

\Delta = 0.135Mpa

PART B) Considering the pressure gauge of the group as the ideal so that at a height H the water cannot flow even if it is open we have to,

P_2 = H\rho g

2.1*10^5 = H (1000)(9.8)

H = 21.42m

Therefore the high which could a faucet be before no water would flow from it is 21.42m

5 0
3 years ago
Which one of the following is not a balanced equation?
tekilochka [14]
(b)equation is not balanced
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3 years ago
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