1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tiny-mole [99]
3 years ago
14

An airplane is flying in a horizontal circle at a speed of 100 m/s. The 80.0 kg pilot does not want the centripetal acceleration

to exceed 7.00 times free-fall acceleration.
Physics
1 answer:
Tema [17]3 years ago
3 0

Answer:

The force will be "5,488". A further solution is provided below.

Explanation:

The given values are:

speed,

v = 100m/s

mass,

m = 80 kg

acceleration,

a = 7

Now,

Radius will be:

⇒ r=\frac{v^2}{ac}

⇒    =\frac{(100)^2}{7\times 9.8}

⇒    =\frac{10000}{68.6}

⇒    =145.77

Force will be:

⇒ F=m\times ac

⇒     =80\times 68.6

⇒     =5488

You might be interested in
The maximum current output of a 60 ω circuit is 11 A. What is the root mean square voltage of the circuit?
goldenfox [79]

Answer:

660V

Explanation:

V=IR

V=?, I=11A,R=60w

V=60 ×11

=660V

8 0
3 years ago
The correctly balanced equation for H 2O 2 → H 2O + O 2 is
antoniya [11.8K]
2H2O + O2 -- 2H2O + O2 .
3 0
3 years ago
It is weigh-in time for the local under 85 kg rugby team. The bathroom scale used to assess eligibilty can be described by Hooke
Varvara68 [4.7K]
<span>k = 1.7 x 10^5 kg/s^2 Player mass = 69 kg Hooke's law states F = kX where F = Force k = spring constant X = deflection So let's solve for k, the substitute the known values and calculate. Don't forget the local gravitational acceleration. F = kX F/X = k 115 kg* 9.8 m/s^2 / 0.65 cm = 115 kg* 9.8 m/s^2 / 0.0065 m = 1127 kg*m/s^2 / 0.0065 m = 173384.6154 kg/s^2 Rounding to 2 significant figures gives 1.7 x 10^5 kg/s^2 Since Hooke's law is a linear relationship, we could either use the calculated value of the spring constant along with the local gravitational acceleration, or we can simply take advantage of the ratio. The ratio will be both easier and more accurate. So X/0.39 cm = 115 kg/0.65 cm X = 44.85 kg/0.65 X = 69 kg The player masses 69 kg.</span>
4 0
3 years ago
Read 2 more answers
Help pls!!
STatiana [176]
The correct answer would be C
5 0
3 years ago
Read 2 more answers
Usually, when the temperture is increased l, what will happen to the ratevof dissolving?
pochemuha
<span>When temperature is increased, the rate of dissolving increases. The kinetic energy of the molecules of the solute and solvent molecules is high thereby increasing their contact. An example is mixing powdered sugar to the water. When you add water to the sugar, the dissolving process is slow. However, when you increase the temperature of the water by boiling it, the sugar dissolves immediately. </span>
3 0
3 years ago
Other questions:
  • You are sitting in your car at rest at a traffic light with a bicyclist at rest next to you in the adjoining bicycle lane. As so
    8·1 answer
  • A police car is at rest parallel to the highway and measures the speed of cars. It sends the signal with a frequency of 1200 Hz,
    15·1 answer
  • A cyclist rides in a circle with speed 8.1 m/s. What is his centripetal acceleration if the circle has a radius of 27 m? A. 3.3
    9·1 answer
  • If a 42kg rolling object slows from 11.5 m/s to 3.33 m/s how much work does friction do?
    6·1 answer
  • When waves are closely spaced together, how would you describe the pitch that you hear?
    13·2 answers
  • While playing a scavenger hunt game, Anthony walks 48.0 m to the south and then walks 12.0 m to the west. What single straight-l
    12·1 answer
  • 2. Which energy sources (input) cause the solar panels to generate electrical energy?
    15·1 answer
  • A bulldozer does a work of 50,000
    15·1 answer
  • Which best compares and contrasts Banking and Investment Planning?
    13·1 answer
  • According to the law of conservation of energy, which statement must be true?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!