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Nikolay [14]
3 years ago
8

What is the gravitational potential energy with respect to the surface of the water of a 75.0-kilogram diver located 3.00 meters

above the water
Physics
1 answer:
Rama09 [41]3 years ago
5 0

Answer:

2205J

Explanation:

Potential energy = mgh

where g is acceleration due to gravity=9.8m/s^{2}

m is mass of the body

h is height

m=75kg    , h=3m

P.E= 75*9.8*3

 =2205J

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An object is given a very small amount of charge. Which of the following could
spayn [35]

5.4*10^-19 C

Explanation:

For the purposes of this question, charges essentially come in packages that are the size of an electron (or proton since they have the same magnitude of charge). The charge on an electron is -1.6*10^-19

Therefore, any object should have a charge that is a multiple of the charge of an electron - It would not make sense to have a charge equivalent to 1.5 electrons since you can't exactly split the electron in half. So the charge of any integer number of electrons can be transferred to another object.

Charge = q(electron)*n(#electrons)

Since 5.4/1.6 = 3.375, we know that it can not be the right answer because the answer is not an integer.

If you divide every other option listed by the charge of an electron, you will get an integer number.

(16*10^-19 C)/(1.6*10^-19C) = 10

(-6.4*10^-19 C)/(1.6*10^-19C) = -4

(4.8*10^-19 C)/(1.6*10^-19C) = 3

(5.4*10^-19 C)/(1.6*10^-19C) = 3.375

(3.2*10^-19C)/(1.6*10^-19C) = 2

etc.

I hope this helps!

3 0
2 years ago
What is the relationship between sunspots and geomagnetic storms?
shutvik [7]
Sunspots are spot like structure on the surface of sun, they are created due to geomagnetic flux which inhibits the convection of heat waves thus reducing the temperature of spot with some factor
8 0
3 years ago
HEY CAN ANYONE PLS ANSWER DIS!!!!!!!!!!!!!!!
Troyanec [42]

Answer:

Explanation:

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3 0
3 years ago
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Help me PLEASE! 25 points!!!!! :)
NeTakaya

Answer:

A.

Explanation:

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7 0
2 years ago
A uniformly charged, straight filament 7.00m in length has a total positive charge of 2.00μC. An uncharged card-board cylinder 2
TEA [102]

The electric field at the surface of the cylinder is 51428V/m

Given data:

• The length of the charge is l=  7m.

• The charge is q = 2μC..

• The radius the cylinder is r = 10 cm

Since the filament length is so large as compared to the cylinder length that the infinite line of charge can be assumed.

The expression to calculate the electric field is given as,

E=2kλ/r

Here, λ is the linear charge density.

Substitute the values in the above equation,

E = (2×9×109N⋅m^2/C^2×2×10^−6C)/0.1m×7m

E = 51428N/C×(V/m)/(N/C)

=51428V/m

An electric charge is the property of matter where it has more or fewer electrons than protons in its atoms. Electrons carry a negative charge and protons carry a positive charge. Matter is positively charged if it contains more protons than electrons, and negatively charged if it contains more electrons than protons.

Learn more about charge here:

brainly.com/question/19886264

#SPJ4

4 0
1 year ago
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