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marshall27 [118]

3 years ago

14

The word gymnosperm comes from two Greek words: gymno, meaning bare, and sperm, meaning_____ . Unlike other seed plants, gymnosp

erms do not have a protective _______ around their seeds. Most gymnosperms have needle-like or scale-like ______.

1 answer:

FrozenT [24]3 years ago

8 0

Answer:

Seed, Fruit, Leaves

Explanation:

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If a certain gas occupies a volume of 12 l when the applied pressure is 6.0 atm , find the pressure when the gas occupies a volu

dolphi86 [110]

From Boyle's law, the volume of a fixed mass of a gas is inversely proportional to its pressure at constant absolute temperature.
Therefore; P1V1 =P2V2; where PV is a constant
hence; 12 × 6 = 3× p2
p2 = 72/3
= 24 atm
Therefore; the new pressure will be 24 atm

5 0

3 years ago

Dmitry [639]

Answer: 176.4 J

Explanation:

5 0

3 years ago

Sammy squirrel is steering his boat at a heading of 327 degree at 18mph. The current is flowing at 4mph at a heading of 60 degre

Tanya [424]

Answer:

59.97 º at 18.23 mph

Explanation:

To find Sammy's course you have to add the two velocities (vectors), 18 mph 327º and 4 mph 60º.

To add the two vectors analytically you decompose each vector into their vertical and horizontal components.

<u>1. 18 mph 327º</u>

Horizontal component: 18 mph × cos (327º) = 15.10 mph

Vertical component: 18 mph × sin (327º) = - 9.80 mph

Vector notation:

$15.10\hat i-9.80\hat j$

<u>2. 4 mph 60º</u>

Horizontal component: 4 mph × cos (60º) = 2.00 mph

Vertical component: 4 mph × sin (60º) = 3.46 mph

Vector notation:

$2.00\hat i+3.46\hat j$

<u>3. Addition:</u>

You add the corresponding components:

$15.10\hat i-9.80\hat j+2.00\hat i+3.46\hat j\\ \\ 17.10\hat i-6.34\hat j$

To find the magnitude use Pythagorean theorem:

$\sqrt{17.1^2+6.34^2}= 18.23$

<u>4. Direction:</u>

Use the tangent ratio:

$tan(\alpha )=opposite/adjacent=3.46/2.00=1.73$

Find the inverse:

arctan (1.73) ≈ 59.97º

5 0

3 years ago

Three point charges lie in a straight line along the y-axis. a charge of q1 = -9.10 µc is at y = 6.30 m, and a charge of q2 = -7

inysia [295]

Answer:

Electric field E = kQ/r^2

Distance between charges = 6.30 - (-4.40) = 10.70m

Say the neutral point, P, is a distance d from q1. This means it is a distance (10.70 - d) from q2.

Field from q1 at P = k(-9.50x^10^-6) / d^2

Field from q2 at P = k(-8.40x^10^-6) / (10.70-d)^2

These fields are in opposite directions and are equal magnitudes if the resultant field = 0

k(-9.50x^10^-6) / d^2 = k(-8.40x^10^-6) / (10.70-d)^2

9.50 / d^2 =8.40 / (10.70-d)^2

d^2 / (10.70-d)^2 = 9.50/8.40 = 1.131

d/(10.70-d) = sqrt(1.1331) = 1.063

d = 1.063 ((10.70-d)

= 10.63 - 1.063d

2.063d = 10.63

d = 5.15m

The y coordinate where field is zero is 6.30 - 5.15 = 1.15m

Explanation:

4 0

4 years ago

When two point charges are a distance d part, the electric force that each one feels from the other has magnitude F. In order to

Serjik [45]

Answer:

E) d/sqrt2

Explanation:

The initial electric force between the two charge is given by:

$F=k\frac{q_1 q_2}{d^2}$

where

k is the Coulomb's constant

q1, q2 are the two charges

d is the separation between the two charges

We can also rewrite it as

$d=\sqrt{k\frac{q_1 q_2}{F}}$

So if we want to make the force F twice as strong,

F' = 2F

the new distance between the charges would be

$d'=\sqrt{k\frac{q_1 q_2}{(2F)}}=\frac{1}{\sqrt{2}}\sqrt{k\frac{q_1 q_2}{(2F)}}=\frac{d}{\sqrt{2}}$

so the correct option is E.

8 0

3 years ago