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marshall27 [118]

3 years ago

14

The word gymnosperm comes from two Greek words: gymno, meaning bare, and sperm, meaning_____ . Unlike other seed plants, gymnosp

erms do not have a protective _______ around their seeds. Most gymnosperms have needle-like or scale-like ______.

1 answer:

FrozenT [24]3 years ago

8 0

Answer:

Seed, Fruit, Leaves

Explanation:

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You are riding a bicycle. If you apply a forward force of 125 N, and you and

erica [24]

Answer:

1.52g

Explanation:

Given parameters:

Force = 125N

Mass combined = 82kg

Unknown:

Acceleration of the bicycle = ?

Solution:

From Newton second law of motion suggests that:

Force = mass x acceleration

Acceleration = $\frac{force}{mass}$ = $\frac{125}{82}$ = 1.52g

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3 years ago

Why do we say that a baseball falls toward Earth, and not Earth toward the baseball?

mezya [45]

Probably because the earth is stationary rotating on its axis whereas the baseball is the one doing all of the movement after being thrown

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3 years ago

When jogging outside you accidentaly bumb into a curb. Your feet stop but your body continues to movr foward and you end up on t

sattari [20]

B.) Newtons first law of motion

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3 years ago

Read 2 more answers

The two speakers at S1 and S2 are adjusted so that the observer at O hears an intensity of 6 W/m² when either S1 or S2 is sounde

Zanzabum

Answer:

The minimum frequency is 702.22 Hz

Explanation:

The two speakers are adjusted as attached in the figure. From the given data we know that

$S_1 S_2$ =3m

$S_1 O$ =4m

By Pythagoras theorem

$S_2O=\sqrt{(S_1S_2)^2+(S_1O)^2}\\S_2O=\sqrt{(3)^2+(4)^2}\\S_2O=\sqrt{9+16}\\S_2O=\sqrt{25}\\S_2O=5m$

Now

The intensity at O when both speakers are on is given by

$I=4I_1 cos^2(\pi \frac{\delta}{\lambda})$

Here

I is the intensity at O when both speakers are on which is given as 6 $W/m^2$

I1 is the intensity of one speaker on which is 6 $W/m^2$

δ is the Path difference which is given as

$\delta=S_2O-S_1O\\\delta=5-4\\\delta=1 m$

λ is wavelength which is given as

$\lambda=\frac{v}{f}$

Here

v is the speed of sound which is 320 m/s.

f is the frequency of the sound which is to be calculated.

$16=4\times 6 \times cos^2(\pi \frac{1 \times f}{320})\\16/24= cos^2(\pi \frac{1f}{320})\\0.667= cos^2(\pi \frac{f}{320})\\cos(\pi \frac{f}{320})=\pm0.8165\\\pi \frac{f}{320}=\frac{7 \pi}{36}+2k\pi \\ \frac{f}{320}=\frac{7 }{36}+2k \\\\ {f}=320 \times (\frac{7 }{36}+2k )$

where k=0,1,2

for minimum frequency $f_1$ , k=1

${f}=320 \times (\frac{7 }{36}+2 \times 1 )\\\\{f}=320 \times (\frac{79 }{36} )\\\\ f=702.22 Hz$

So the minimum frequency is 702.22 Hz

5 0

3 years ago

Is the acceleration change or constnt?

marin [14]

Change.

Acceleration means going faster

4 0

2 years ago