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3 years ago

What is the Greatest Common Factor of 8 and 36?

Mathematics

2 answers:

vovikov84 [41]3 years ago

5 0

I believe that the answer is 4.
4*2=8
4*9=36
:)

Hope this helps!

dem82 [27]3 years ago

3 0

The factors of 8 are: 1, 2, 4, 8

The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, 36

Then the greatest common factor is 4.

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Will mark Brainliest!! :)

Georgia [21]

Step-by-step explanation:

The system of equations for eq 1 which is 3x + y = 118 represents the Green High School which filled three buses(with a specific number of students identified as x) and a van(with a specific number of students identified as y) with a total of 118 students.

for eq 2; 4x + 2y = 164; represents Belle High School which filled four buses(with a specific number of students identified as x) and two vans(with a specific number of students identified as y) with a total of 164 students.

The solution represents the specific number of students in the buses and vans in eq1 and eq 2 with x being 36 students and y being 10 students.

substituting 36 for x and 10 for y in eq 1;

3(36) + 10 = 108 + 10 = 118 total students for Green High School

substituting 36 for x and 10 for y in eq2;

4(36) + 2(10) = 144 + 20 = 164 total students for Belle High school

6 0

2 years ago

The riding stables just received an unexpected rush of registrations for the next horse show, and quickly needs to create some a

liraira [26]

Answer:

Maximum added area will be 60,000 ft²

Each paddock measure 200 ft by 150 ft, and the paddocks share a 200-ft long side.

Step-by-step explanation:

Consider the provided information.

There is sufficient funding to rent 1200 feet of temporary chain-link fencing.

The plan is to form two paddocks with one shared fence running down the middle.

The total length of fencing is 1200 feet that is same as the total perimeter including that shared line down the middle.

Therefore, the perimeter is

$P = 1200 = 2L + 3w$

Solve for L

$1200-3w = 2L$

$L=600-\frac{3w}{2}$

As we know the area of rectangle is A=L×W

Substitute the value of L in above formula.

$A=(600-\frac{3w}{2})\times w\\A=600w-\frac{3w^2}{2}$

$A=-\frac{3w^2}{2}+600w$

The above equation makes a downward parabola.

In order to find the maximum, find the vertex of parabola as shown:

$W=\frac{-b}{2a}=\frac{600}{2\times\frac{3}{2}}=200$

Hence, the width should be 200 ft in order to get maximum area,

Therefore, the length will be:

$1200 = 2L + 3(200)$

$L=300$

Now substitute the value of L and W in area formula.

A=300×200=60,000

Hence, maximum added area will be 60,000 ft²

Hence, the length should be 300 ft, and each paddock should then be 150 feet long.

Each paddock measure 200 ft by 150 ft, and the paddocks share a 200-ft long side.

5 0

3 years ago

The triangles shown below must be congruent.

Ber [7]

Answer:

False

Step-by-step explanation:

The triangles are similar because the angles are the same

We know nothing about the side lengths, so we can say nothing about concurrency. They may or may not be congruent.

4 0

3 years ago

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One and read or both rode bicycles from the park to Main Street the graphs below represent the time and distance for each studen

Harman [31]

Juan did.

The line on his graph takes longer to get to 8 blocks.;-D

7 0

3 years ago

The following table shows the values of y for different values of x:

solmaris [256]

Answer:

Option B. It represents a nonlinear function because its points are not on a straight line.

Step-by-step explanation:

Let

$A(0,0),B(1,1),C(2,4)$

we know that

If point A,B and C are on a straight line

then

The slope of AB must be equal to the slope of AC

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

Find the slope AB

$A(0,0),B(1,1)$

substitute in the formula

$m_A_B=\frac{1-0}{1-0}=1$

Find the slope AC

$A(0,0),C(2,4)$

substitute in the formula

$m_A_C=\frac{4-0}{2-0}=2$

$m_A_B\neq m_A_C$

Points A, B and C are not on a straight line

therefore

It represents a nonlinear function because its points are not on a straight line

8 0

3 years ago

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