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Kitty [74]
3 years ago
8

Write a computer program that determines how many grades are between 0 and 19.

Computers and Technology
1 answer:
True [87]3 years ago
7 0

Answer:

public class nnn {

   public static void main(String[] args) {

       int [] examScores = {31, 70, 92, 5, 47, 88, 81, 73, 51, 76, 80, 90, 55, 23, 43,98,36,87,22,61, 19,69,26,82,89,99, 71,59,49,64};

       int zeroTo19 = 0;

       int nineteenTo39 = 0;

       int fortyTo59 = 0;

       int sixtyTo79 = 0;

       int eightyTo100 = 0;

       for(int i =0; i<examScores.length; i++){

           if(examScores[i]<=19){

               zeroTo19++;

           }

           else if(examScores[i]>19&&examScores[i]<=39){

               nineteenTo39++;

           }

           else if(examScores[i]>39&&examScores[i]<=59){

               fortyTo59++;

           }

           else if(examScores[i]>59&&examScores[i]<=79){

               sixtyTo79++;

           }

           else {

               eightyTo100++;

           }

       }

       System.out.println("0 - 19 is "+zeroTo19);

       System.out.println("20 - 39 is "+nineteenTo39);

       System.out.println("40 - 59 is "+fortyTo59);

       System.out.println("60 - 79 is "+sixtyTo79);

       System.out.println("80 - 100 is "+eightyTo100);

   }

}

Explanation:

  • This has been solved with Java
  • Create an array of the exam scores
  • Create new variables for each of the score range
  • Use multiple if statements as u loop through the array to determine the range of scores
  • Finally outside the loop print them variables out
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Answer:

Check the explanation

Explanation:

MATLAB code:

%----------------------

function result = dominant(A)

% matrix dimensions

d = size(A);

% for loop over rows

for i = 1:d

% sum of row elements except diagonal element

sum_row =0;

% for loop over columns

for j = 1:d

% adding each elements to sum variable

sum_row = sum_row+ abs(A(i,j));

end

%subratcting diagonal element

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%checking dominant condition

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if abs(A(i,i))< sum_row

result = 'false';

return;

end

end

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result = 'true';

end

% matrix A

A = [ 3 -2 1; 1 -3 2; 1 2 6]

% result

result = dominant(A)

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% result

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%----------------------

Kindly check the attached output image below.

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Explanation:

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Answer:

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