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Alexxx [7]
4 years ago
6

The area of the rectangle shown is 2x^2-x-15 square units. What is the width of the rectangle?

Mathematics
1 answer:
yuradex [85]4 years ago
3 0

Answer:

<h2>The width is (2x + 5) or (x - 3)</h2>

Step-by-step explanation:

The formula of an area of a rectangle:

A=lw

l - length

w - width

We have

A=2x^2-x-15

2x^2-x-15=2x^2+5x-6x-15=x(2x+5)-3(2x+5)\\\\=(2x+5)(x-3)

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kvv77 [185]

Answer: BCD

Step-by-step explanation:

A is incorrect since there is no angle Y to exist

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3 years ago
10 points And thank you for whoever answers
Yuri [45]

Answer:

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6 0
3 years ago
How wil the graph of the function y=x^3 transform when changed to y=x^3+4
dem82 [27]

Every point on the original graph will move up 4 units. See the enclosed graph

Legend

Red: y = x^3

Blue: y = x^3 + 4

Green: A vertical line that shows that when x = 1 on the original red graph, x = 5 on the blue.

4 0
3 years ago
The Sharadze family is planning a car trip to Atlanta Georgia which is 279 miles from their home. Thy plan to drive at an averag
labwork [276]

Answer:

8:45

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4 0
3 years ago
Read 2 more answers
In a sample of 16 employees randomly selected at a company, the average age is 25 years and the standard deviation is 2 years. W
pentagon [3]

If ages are normally distributed then using a significance level of 0.05 , we can claim that the population mean is greater than 24.

Given sample mean of 25 years , sample size of 16 ,standard deviation of 2 years.

We have to find whether the population average is greater than 24.

We have to use t test because n is less than 30. It is right tailed.

We have to first form Hypothesis.

H_{0}:μ>24,

H_{1}:μ<24.

t=X-μ/S/\sqrt{n}

t critical at 5% significance level and degree of freedom=15    (16-1)=1.7531

t=24-25/2/\sqrt{16}

=-1/0.5

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Because 1.7531 is greater than -2 so we will accept the null hypothesis.

Hence we can say that the average of population is greater than 24.

Learn more about t test at brainly.com/question/6589776

#SPJ4

8 0
2 years ago
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