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Alexxx [7]
3 years ago
6

The area of the rectangle shown is 2x^2-x-15 square units. What is the width of the rectangle?

Mathematics
1 answer:
yuradex [85]3 years ago
3 0

Answer:

<h2>The width is (2x + 5) or (x - 3)</h2>

Step-by-step explanation:

The formula of an area of a rectangle:

A=lw

l - length

w - width

We have

A=2x^2-x-15

2x^2-x-15=2x^2+5x-6x-15=x(2x+5)-3(2x+5)\\\\=(2x+5)(x-3)

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3 years ago
Evaluate the definite integral. <br> 1 x4(1 + 2x5)5 dx.
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Answer:

Step-by-step explanation:

Given the definite integral \int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx, we to evaluate it. Using integration by substitution method.

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du/dx = -10x⁴

dx = du/-10x⁴.... 2

Substitute equation 1 and 2 into the integral function and evaluate the resulting integral as shown;

= \int\limits {\dfrac{x^4}{u^5} } \, \dfrac{du}{-10x^4}

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substitute u = 1-2x⁵ into the result

= \dfrac{1}{40(1-2x^5)^4} +C

Hence\int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx = \dfrac{1}{40(1-2x^5)^4} +C

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2 years ago
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2 years ago
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Galina-37 [17]

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Step-by-step explanation:

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