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3 years ago

The area of the rectangle shown is 2x^2-x-15 square units. What is the width of the rectangle?

Mathematics

1 answer:

yuradex [85]3 years ago

3 0

Answer:

<h2>The width is (2x + 5) or (x - 3)</h2>

Step-by-step explanation:

The formula of an area of a rectangle:

$A=lw$

l - length

w - width

We have

$A=2x^2-x-15$

$2x^2-x-15=2x^2+5x-6x-15=x(2x+5)-3(2x+5)\\\\=(2x+5)(x-3)$

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2 years ago

The mean of five numbers is 6 the median is 7 and the mode is 2. What is the answer?

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Answer:

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2 years ago

What is the slope of the line that passes through the pair of points (1/3, -1) and ( -2, 9/2)

UkoKoshka [18]

Answer:

$\boxed{m = - \frac{33}{14} }$

Step-by-step explanation:

Use the form below

$\boxed{\boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }}$

Where

$m$ is a slope
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So, the slope is

$(\frac{1}{3} ,~ -1) \to x_1 = \frac{1}{3} ~and~y_1 = -1$

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7 0

3 years ago

Read 2 more answers

Determine the total numbers of zero<br> f(x) = 23 – 3x2 – 2x + 6

AleksandrR [38]

Answer:

f(x) = 29

Step-by-step explanation:

f(x)=23-(3x0)-(2X0)+6

f(x)=23+6

f(x)=29

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3 years ago

Solve for w.<br> 8(w+2) = 40

AleksAgata [21]

Answer:

w = 3

Step-by-step explanation:

8 • (w + 2) - 40 = 0

Pulling out like terms :

3.1 Pull out like factors :

8w - 24 = 8 • (w - 3)

Equation at the end of step 3 :

8 • (w - 3) = 0

Step 4 :

Equations which are never true :

4.1 Solve : 8 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

4.2 Solve : w-3 = 0

Add 3 to both sides of the equation :

w = 3

One solution was found :

w = 3

Processing ends successfully

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