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Finger [1]
3 years ago
6

A garden has a perimeter of 56 square feet. The width of the garden

Mathematics
2 answers:
Alja [10]3 years ago
6 0
The answer to this question is 98
Irina-Kira [14]3 years ago
4 0

Answer:

98

Step-by-step explanation:

As it is a little bit of a few questions about the other one I have to the store go back tomorrow and will get back tomorrow and I have been working

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If your score on a computer game is less than 0, you lose your next turn. For what scores will you lose your turn? Write an ineq
spayn [35]

Answer:0

Step-by-step explanation:

7 0
2 years ago
HELP HELP PLEASE!!!!!
klio [65]
  1. This problem requires the pathagoriun theorum. The formula is a² + b² = c², which basically means that If you square the two sides that are already labeled, then add them, you will get the length of the side that is unknown.
  2. In this equation, we are given the length of the shortest side, which is 21m. I believe that the length of the side CA is twice the length of the side BC, which would be 42m.
  3. Now you find the square of both, and add them. 21² + 42² (or 441 + 1764) is 2205.
  4. Since the square of 2205 is a decimal, (it is 46.9574275275) you will round it to the nearest whole number, which is 47.

<h2>47</h2>
3 0
2 years ago
Need Help Please I'm Out Of Time ;(
STatiana [176]

Answer:

last three questions are statistical question

5 0
2 years ago
Butch, Harry, and Nicky are playing a game. Harry has half as many points as
ryzh [129]

Answer:

9

Step-by-step explanation:

H=1/2 * B

N=H-5= 1/2 * B-5

B+H+N= B+(1/2 *B) + (1/2 *B-5)=31

2B-5=31

B=18

H=1/2 *B=9

4 0
3 years ago
A certain CD-ROM disk can store approximately 6.0 × 102 megabytes of information, where 106 bytes = 1 megabyte. If an average wo
klemol [59]

Answer: A. 4.3\times10^7

Step-by-step explanation:

Given : A certain CD-ROM disk can store approximately 6.0 \times 10^2  megabytes of information.

1 megabyte = 10^6 bytes

Then, The storage capacity of CD-ROM disk will be :

10^6\times 6.0 \times 10^2=6\times10^{6+2}=6\times10^8  

If an average word requires 14 bytes of storage, then the number of words can be stored :-

\dfrac{6\times10^8}{14}=0.428571428571\times10^8\approx0.43\times10^8=4.3\times10^7

Hence,  number of words can be stored = 4.3\times10^7

4 0
3 years ago
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