Answer:
v = 6.06 m/s
Explanation:
In order for the rider to pass the top of the loop without falling, his weight must be equal to the centripetal force:
where,
v = minimum speed of motorcycle at top of the loop = ?
g = acceleration due to gravity = 9.8 m/s²
r = radius of the loop = diameter/2 = 7.5 m/2 = 3.75 m
Therefore, using these values in equation, we get:
<u>v = 6.06 m/s</u>
Answer:
(1) V=0.03348 gallons
(2) L= 576.813 km .
Explanation:
Write the relation between the density and volume for ethanol.
density ( ρ )= m/V
Volume ( V )= m/ρ .......... (1)
Here, V is the volume of ethanol, m is the mass of ethanol, and is the density of ethanol.
Write the relation between the specific gravity of ethanol and density of water
ρ=γ*ρ(water) ............. (2)
Here, is specific gravity of ethanol and is the density of water.
Determine the volume of ethanol by substituting equation (2) in equation (1)
V=m/γ*ρ(water)
Substitute 100 gm , for m, for , and 1000 kg/m for.
V=
V=0.000112674
Convert m³ to gallons
V= (0.000112674*264.172 )
V=0.03348 gallons
Step 2:
Determine the distance travelled by the special vehicle named “Micro joule” runs with ethanol.
L=C*V .......... (3)
Here, is the rate of consumption of ethanol by Micro joule.
Substitute 10,705 mi/gallons for C and 0.03348 gallons for .
By using eq. 3.
L= 10750*0.03348
L=358.416 mi.
Convert the distance travelled by Micro joule from miles to kilometres
L= (358.416* 1.60934)
L = 576.813 km
Thus, the distance travelled by Micro joule is 576.813 km .