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natulia [17]
2 years ago
8

If two oscillators connected to speakers create frequencies of 594 hz and 600 hz, what is the beat frequency when you hear both

at the same time? hz
Physics
1 answer:
Annette [7]2 years ago
3 0
When we have two sound waves with frequencies f1 and f2 that interfere, the beat frequency is equal to the absolute value of the difference of the two frequencies, so in our problem:
f_{beat}=f_2-f_1 = 600 Hz-594 Hz = 6Hz
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A ball is spun around in circular motion such that it completes 50 rotations in 25 s.
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Answer:

(A) The period of its rotation is 0.5 s (2) The frequency of its rotation is 2 Hz.

Explanation:

Given that,

a ball is spun around in circular motion such that it completes 50 rotations in 25 s.

(1). Let T be the period of its rotation. It can be calculated as follows :

T=\dfrac{25}{50}\\\\T=0.5\ s

(2). Let f be the frequency of its rotation. It can be defined as the number of rotations per unit time. So,

f=\dfrac{50}{25}\\\\f=2\ Hz

Hence, this is the required solution.

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1 year ago
Mount Everest rises to a height of 8,850 m above sea level. At a base camp on the mountain the atmospheric pressure is measured
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Answer:

74.86°C

Explanation:

P₂ = Vapour pressure of water at sea level = 760 mmHg

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From Claussius Clapeyron equation

ln\frac{P_2}{P_1}=\frac{\Delta H}{R}\left(\frac{1}{T_1}-\frac{1}{T_2}\right)\\\Rightarrow ln\frac{760}{296}=\frac{40700}{8.314}\left(\frac{1}{T_1}-\frac{1}{373}\right)\\\Rightarrow ln\frac{760}{296}\times \frac{8.314}{40700}+\frac{1}{373}=\frac{1}{T_1}\\\Rightarrow 0.0028735=\frac{1}{T_1}\\\Rightarrow T_1=347.996\ K

T₁ = 347.996 K = 74.86°C

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4 0
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Answer:

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Explanation:

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3 years ago
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