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Dmitry [639]
1 year ago
10

kg book is lying ona 0.80 m -high table. You pick it up and placeit on a bookshelf 2.2 mabove the floor.a.During this process, h

ow much work does gravity do on thebook. Express your answer to two significant figuresand include the appropriate units.b. During this process, how much work doesyour hand do on the book?Express your answer to two significant figures and include theappropriate units.
Physics
1 answer:
Sergeu [11.5K]1 year ago
8 0

The work done by gravity is  43 J while the work done by your habd is 27 J.

<h3>What is the work done?</h3>

We know that all over the earth is a large gravitational field. If an object is placed at a given height, the kind of energy that the object would be said to possess at that height is the gravitational potential energy. This is the kind of energy that a body would have because it is found at a given height on the earth surface.

Now, we know that gravity does some work on the book as it found to be at a position of about 2.2 on top of the shelf. The work that is done by the force of gravity on the book is obtained as;

W = mgh

W = work done

m = mass

g = acceleration due to gravity

h = height

W = 2 * 9.8 * 2.2

= 43 J

The work that is done by your hand =

W = 2 * 9.8 (2.2 - 0.8)

= 27 J

Learn more about work done:brainly.com/question/10334435

#SPJ1

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Answer:

Option B

Explanation:

<h3>According to Newton's third law, for every reaction there will be equal and opposite reaction</h3>

Here in this case the force of the club hitting the golf ball will be in one direction and the force acting on club due to golf ball will be in opposite direction and magnitude of this force will be same as the magnitude of the force of the club hitting the golf ball

In this case the action will be the force of the club hitting the golf ball and reaction will be the force acting on club due to golf ball

∴ The club pushes against to golf ball with a force equal and opposite to the force of the golf ball on the club  

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Oscilloscopes have parallel metal plates inside them to deflect the electron beam. These plates are called the deflecting plates
Alina [70]

Answer:

The capacitance of the deflecting plates is C=1.59 pF.

Explanation:

The expression for the capacitance of the capacitor in terms of area and distance is as follows;

C=\frac{\varepsilon _{0}A}{d}

Here, C is the capacitance, A is the area, d is the distance and \varepsilon _{0} is the absolute permittivity.

Convert the side of the square from cm to m.

s= 3.0 cm

s= 0.030 m

Calculate the area of the square.

A= s_^{2}

Put s= 0.030 m.

A=(0.030)_^{2}

A=9\times10^{-4}m^{-2}

Convert distance from mm to m.

d= 5.0 mm

d=5\times10^{-3}m

Calculate the capacitance of the deflecting plates.

C=\frac{\varepsilon _{0}A}{d}

Put d=5\times10^{-3}m, A=9\times10^{-4}m^{-2} and \varepsilon _{0}=8.85\times 10^{-12}Fm^{-1}.

C=\frac{(8.85\times 10^{-12})(9\times10^{-4})}{5\times10^{-3}}

C=1.59\times 10^{-12}F

C=1.59 pF

Therefore, the capacitance of the deflecting plates is C=1.59 pF.

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A charge of 0.91 C is spread uniformly throughout a 25 cm rod of radius 4 mm. What are the volume and linear charge densities
Oxana [17]

The volume of the rod is 1.26×10⁻⁵ m³, and the linear charge density of the rod is 3.64 C/m

<h3>What is volume?:</h3>

This is the product of the height of a solid object and its crossectional area.

The Volume of the rod is can be calculated using the formula below.

Note: A rod has the shape of a cylinder.

Formula:

  • V = πr²h............... Equation 1

Where:

  • V = Volume of the rod
  • r = radius of the rod
  • h = height of the rod.

From the question,

Given:

  • r = 4mm = 0.004 m
  • h = 25 cm = 0.25 m
  • π = 3.14

Substitute these values into equation 1

  • V = 3.14(0.004²)(0.25)
  • V = 1.26×10⁻⁵ m³

<h3>What is linear charge density:</h3>

This is the ratio of the charge on an object to the length of the object.

The linear charge density of the rod can be calculated using the formula below.

  • D = Q/h.................... Equation 2

Where:

  • D = Linear charge density of the rod
  • Q = Charge on the rod.
  • h = height or length of the rod

From the question

Given:

  • Q = 0.91 C
  • h = 25 cm = 0.25 m

Substitute these values into equation 2

  • D = 0.91/0.25
  • D = 3.64 C/m

Hence, The volume of the rod is 1.26×10⁻⁵ m³, and the linear charge density of the rod is 3.64 C/m

Learn more about charge density here: brainly.com/question/14568868

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