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GaryK [48]
3 years ago
8

A company has been hired to perform environmental remediation on an area of marshland. What would they most likely do?

Physics
2 answers:
mixas84 [53]3 years ago
8 0

Answer: In order to remediate a marshland area, initially the area must be surveyed and the problems are needed to understand. Once the problems are identified, the necessary steps must be taken such as-

  1. The water quality of the area must be improved if degraded. This restoration of water will help the biota to maintain a healthy ecosystem.
  2. The soil quality also should be tested, that are responsible for the growth and development of various plants. The more fertile is the soil the more vegetation cover it has. The use of chemicals should be reduced.
  3. The waste materials must be removed from the marshland area that pollutes the soil, water as well as the air.
  4. Afforestation must be done.
  5. Awareness programs should be made to maintain a good and healthy marshland.
WINSTONCH [101]3 years ago
4 0

Answer:

remove contamination; pollution ; test ground water and dirt .

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3. Write any two types of force.​
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Answer:

An <u>applied force</u> is a force that is applied to an object by a person or another object. If a person is pushing a desk across the room, then there is an applied force acting upon the object. The applied force is the force exerted on the desk by the person.

A <u>friction force</u> is the force exerted by a surface as an object moves across it or makes an effort to move across it. There are at least two types of friction force - sliding and static friction. Though it is not always the case, the friction force often opposes the motion of an object. For example, if a book slides across the surface of a desk, then the desk exerts a friction force in the opposite direction of its motion. Friction results from the two surfaces being pressed together closely, causing intermolecular attractive forces between molecules of different surfaces. As such, friction depends upon the nature of the two surfaces and upon the degree to which they are pressed together. The maximum amount of friction force that a surface can exert upon an object can be calculated using the formula below:

F_{frict} = µ • F_{norm}

8 0
2 years ago
A runner runs 2.0 km in 5.0 minutes
Nadya [2.5K]

Answer: What is this supposed to be converted into?

Explanation:

4 0
3 years ago
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what happens to the current in a circuit if the resitance of the components in the circuit is increased​
Anit [1.1K]

Answer:

The current decreases.

Explanation:

Current and resistance are inversely proportional. The equation connecting current, resistance and voltage is V = IR, where V is voltage, I is current and R is resistance.

Rearranging this equation, you get:

I = \frac{V}{R}

and

R = \frac{V}{I}

If the value of voltage in both equations remains constant, and the value of R decreases, the value of I will increase. Conversely, if in the second equation R = \frac{V}{I} , the value of V remains constant the value of I decreases, then the value of R, resistance will increase.

Thus, it can be seen that the current will decrease as resistance increases and vice versa.

7 0
3 years ago
A bond between two copper atoms would be a<br> bond? *
mihalych1998 [28]
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2 years ago
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You want to lean your dad's ladder on a smooth wall. If the mass of ladder is 4.42 kg and coefficient
iren [92.7K]

Answer:

angle minimum   θ = 41.3º

Explanation:

For this exercise let's use Newton's second law in the condition of static equilibrium

    N - W = 0

    N = W

The rotational equilibrium condition, where we place the axis of rotation on the wall

We assume that counterclockwise rotations are positive

     fr (l sin θ) - N (l cos θ) + W (l/2 cos θ) = 0

     

the friction force formula is

     fr = μ N

     fr = μ W

we substitute

      μ m g l sin θ - m g l cos θ + mg l /2   cos θ = 0

      μ sin θ - cos θ + ½ cos θ= 0

         

       μ sin θ - ½ cos θ = 0

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       tan θ = 1/2 μ

       θ = tan⁻¹ (1 / 2μ)

       θ = tan⁻¹ (1 (2 0.57))

      θ = 41.3º

7 0
3 years ago
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