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3 years ago

A company has been hired to perform environmental remediation on an area of marshland. What would they most likely do?

2 answers:

8 0

Answer: In order to remediate a marshland area, initially the area must be surveyed and the problems are needed to understand. Once the problems are identified, the necessary steps must be taken such as-

The water quality of the area must be improved if degraded. This restoration of water will help the biota to maintain a healthy ecosystem.
The soil quality also should be tested, that are responsible for the growth and development of various plants. The more fertile is the soil the more vegetation cover it has. The use of chemicals should be reduced.
The waste materials must be removed from the marshland area that pollutes the soil, water as well as the air.
Afforestation must be done.
Awareness programs should be made to maintain a good and healthy marshland.

WINSTONCH [101]3 years ago

4 0

Answer:

remove contamination; pollution ; test ground water and dirt .

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A sample of 5.6 L of a gas is at a pressure of 1.5 atm. If the volume of the gas is compressed to 4.8 L, what will the new press

Effectus [21]

Answer:

1.75atm

Explanation:

According to Boyle's law, the pressure P of a fixed mass of gas is inversely proportional to it's volume V provided that the temperature remains constant.

$P\alpha \frac{1}{V}\\hence\\PV=constant$

This implies the following;

$P_1V_1=P_2V_2=...=P_nV_n............(1)$ Provided temperature is kept constant.

Given;

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From equation (1), we can write;

$P_1V_1=P_2V_2\\hence\\1.5*5.6=P_2*4.8\\\\P_2=\frac{1.5*5.6}{4.8}\\\\P_2=1.75atm$

Since all the units are consistent, there is no need for conversion.

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2 years ago

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A sample of chloroform is found to contain 12.0 g of carbon, 106.4 g of chlorine, and 1.01 g of hydrogen. If a second sample of

GREYUIT [131]

Given:

Sample 1:

Chloroform is $CHCl_{3}$

12 g Carbon

1.01 g Hydrogen

106.4 g Cl

Sample 2:

30.0 g of Carbon

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mass of chloroform from sample 1:

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mass of chloroform $\times$ $\frac{given mass of carbon}{mass of carbon atom}$

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