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GaryK [48]
3 years ago
8

A company has been hired to perform environmental remediation on an area of marshland. What would they most likely do?

Physics
2 answers:
mixas84 [53]3 years ago
8 0

Answer: In order to remediate a marshland area, initially the area must be surveyed and the problems are needed to understand. Once the problems are identified, the necessary steps must be taken such as-

  1. The water quality of the area must be improved if degraded. This restoration of water will help the biota to maintain a healthy ecosystem.
  2. The soil quality also should be tested, that are responsible for the growth and development of various plants. The more fertile is the soil the more vegetation cover it has. The use of chemicals should be reduced.
  3. The waste materials must be removed from the marshland area that pollutes the soil, water as well as the air.
  4. Afforestation must be done.
  5. Awareness programs should be made to maintain a good and healthy marshland.
WINSTONCH [101]3 years ago
4 0

Answer:

remove contamination; pollution ; test ground water and dirt .

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Why do land animals including meat eaters depend on soil
dexar [7]
They depend on it because this helps them maintain nutirance and survive and reproduce more.
4 0
3 years ago
How is the Milky Way changing? A. Large numbers of stars are being born inside nebulas. B. The Milky Way does not change. C. Lar
Over [174]

Answer:

D. Large numbers of stars are undergoing blue-shift.

Explanation:

The Milky Way is changing because a large numbers of stars are undergoing blue-shift.

7 0
3 years ago
Determine the image distance and image height for a 5.00 cm tall object placed 30.0 cm from a double convex lens with a focal le
vlabodo [156]

Answer:

The image distance is 30 cm

image height = - 5 cm

Explanation:

The formula for calculating the image distance is expressed as

1/f = 1/u + 1/v

where

f is the focal length

u is the object distance

v is the image distance

From the information given,

u = 30

f = 15

By substituting these values into the formula,

1/15 = 1/30 + 1/v

1/v = 1/15 - 1/30 = (2 - 1)/30 = 1/30

Taking the reciprocal of both sides,

v = 30

The image distance is 30 cm

magnification = image height/object height = - v/u

Given that object height = 5 cm, then

image height/5 = - 30/30 = - 1

image height = - 5 * 1

image height = - 5 cm

8 0
1 year ago
Which model shows how an image appears to a person when they look through a concave lens?
slava [35]
What models are you talking about
7 0
2 years ago
Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 20 cm apart. The sound
Sophie [7]

Answer:

a. Wavelength = λ = 20 cm

b. Next distance of maximum intensity will be 40 cm

Explanation:

a. The distance between the two speakers is 20cm. SInce the intensity is maximum which refers that we have constructive interference and the phase difference must be an even multiple of π and equivalent path difference is nλ.

Now when distance increases upto 30 cm between the speakers, the sound intensity becomes zero which means that there is destructive interference and equivalent path is now increased from nλ to nλ + λ/2.

This we get the equation:

(nλ + λ/2) - nλ = 30-20

λ/2 = 10

λ = 20 cm

b. at what distance, sound intensity will be maximum again.

For next point calculation for maximum sound intensity, the path difference must be increased (n+1) λ. The distance must increase by λ/2 from the point of zero intensity.

= 30 + λ/2

= 30 + 20/2

=30+10

=40 cm

7 0
3 years ago
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