Part (a)
Plug in y = 0 and solve for x. Use the zero product property
y = x(x+3)(x-2)
0 = x(x+3)(x-2)
x(x+3)(x-2) = 0
x = 0 or x+3 = 0 or x-2 = 0 .... zero product property
x = 0 or x = -3 or x = 2
The three roots or zeros are x = 0 or x = -3 or x = 2
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Part (b)
The roots of the graph are: x = -2, x = 1, x = 3. Each root is where the graph crosses or touches the horizontal x axis.
Note how x = 0 is found in part (a), but not found here. This is one example where the graphs don't match. Another would be x = -3 is in part (a), but not here.
So that's why the graph does <u>not</u> match with the function in part (a)
Respuesta:
Allí está el proceso, de nada <3
Answer:
yeah guys i also want to know that questian
60£
Peter = 2 Angard
Angard = 3 Nick
Peter = 2 Angard = 6 Nick
Angard = 3 Nick
Nick = 1 Nick
6+3+1=10 Nick
60£/10 = 6£
Nick = 6£
Angvard = 3 Nick = 6£*(3) = 18£
Peter = 6 Nick = 6£*(6) = 36£
(prove: 6+18+36=60£)
Answer:
you can do 3 x 6 + 8 - 2
Step-by-step explanation:
3 × 6= 18
+8= 26
-2= 24
hope this Helps :)
