1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kati45 [8]
3 years ago
5

Find the sum: 413+11 12 0 15 15 0 1513 0263 48-15

Mathematics
1 answer:
Setler79 [48]3 years ago
7 0

Answer:

26\sqrt{3}

Step-by-step explanation:

Pull terms out from under the radical, assuming positive real numbers.

You might be interested in
The rectangular floor of a storage shed has an area of 580 square feet. The length of the floor is 9 feet more than its width (s
Marysya12 [62]

9514 1404 393

Answer:

  • length: 29 ft
  • width: 20 ft

Step-by-step explanation:

Assuming the dimensions are integer numbers of feet, you're looking for factors of 580 that have a difference of 9.

 580 = 1×580 = 2×290 = 4×145 = 5×116 = 10×58 = 20×29

The last pair of factors differs by 9, so ...

  the length is 29 feet; the width is 20 feet.

8 0
2 years ago
4. 110 in. = _<br>ft_<br>in.​
aliina [53]

Answer:

110 in. = 9  1/6 ft, or 9 ft 2 in

Step-by-step explanation:

Please try to do a better job of formatting your next question.  Thanks.

110 in       1 ft

-------- * --------- = 9 1/6 ft  or  9 ft 2 in

   1          12 in

4 0
3 years ago
Anna and Veronica are on the opposite sides of a tower of 160 meters height. They measure the angle of elevation of the top of t
MAXImum [283]

Answer: The distance between the girls is 362.8 meters.

Step-by-step explanation:

So we have two triangle rectangles that have a cathetus in common, with a length of 160 meters.

The adjacent angle to this cathetus is 40° for Anna, then the opposite cathetus (the distance between Anna and the tower) can be obtained with the relationship:

Tan(A) = opposite cath/adjacent cath.

Tan(40°) = X/160m

Tan(40°)*160m = 134.3 m

Now, we can do the same thing for Veronica, but in this case the angle adjacent to the tower is 55°

So we have:

Tan(55°) = X/160m

Tan(55°)*160m = X = 228.5 m

And we know that the girls are in opposite sides of the tower, so the distance between the girls is equal to the sum of the distance between each girl and the tower, then the distance between the girls is:

Dist = 228.5m + 134.3m = 362.8m

8 0
2 years ago
The area of the shaded segment is 100cm^2. Calculate the value of r.
Reil [10]
Hello, 

The formula for finding the area of a circular region is: A=  \frac{ \alpha *r^{2} }{2}

then:
A_{1} = \frac{80*r^{2} }{2}

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

cos(40)= \frac{h}{r}  \\  \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)

Now we can find its area:
A_{2}=2* \frac{b*h}{2}  \\  \\ A_{2}= [r*sen(40)][r*cos(40)]\\  \\A_{2}= r^{2}*sen(40)*cos(40)

The subtraction of the two areas is 100cm^2, then:

A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm

Answer: r= 1.59cm
7 0
2 years ago
Read 2 more answers
Can someone help me
Colt1911 [192]
The answer is B. (-1,3) hope this helped
3 0
3 years ago
Other questions:
  • If QRST is a rectangle, find the value of x if angle Q is equal to 5x+30
    11·2 answers
  • Put the steps in correct order for the equation Solve 3(2x−7)+5=−19
    12·2 answers
  • if 4 shirts and 3 ties cost 241. and 3 shirts and 4 ties cost 200. what is the cost of 1 shirt and 1 tie?​
    8·1 answer
  • Solve for x and explain your answer
    14·1 answer
  • 5(-2/3)= what is the anwser to this
    13·1 answer
  • Help plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz 10 points
    6·1 answer
  • Which fraction can be used to represent this division problem 5.34 divided by 2.5
    9·1 answer
  • Please help!!!!!!!!!! im struggling
    12·2 answers
  • Can someone please help
    12·2 answers
  • What is the slope of line m? please help
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!