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Salsk061 [2.6K]
3 years ago
8

Match the term with the definition. gas solid plasma Liquid takes the shape and volume of an entire container. charged particles

that do not have a definite shape or volume. assumes the shape of the part of the container from the bottom up. has a fixed volume and shape
Chemistry
1 answer:
Daniel [21]3 years ago
8 0
<h3>Answer:</h3>

Gas: <u>Takes the shape and volume of an entire container</u>.

Solid: <u>Has a fixed volume and shape</u>.

Plasma: <u>Charged particles that do not have a definite shape or volume</u>.

Liquid: <u>Assumes the shape of the part of the container from the bottom up</u>.

<h3>Explanation:</h3>

Due to weak / negligible intermolecular or interatomic forces the gases tends to occupy the shape of the container. Hence, they are said to be having no definit shape and volume.

Due to presence of stronger intermolecular forces as compared to gases liquids have definite volume but they don't have definite shape therefore, adopts the shape of the container from the bottom up.

Solid state of matter is characterized by its hardness, definite shape and volume, rigidity and mechanical strength. They have the strongest intermolecular forces among the molecules.

Plasma is said to be the fourth state of matter, which is the mixture of +ve ions, -ve electrons and neutral particles. It shares majority of the properties of gas state.

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A standard galvanic cell is constructed so that the overall cell reaction is as given below where M is an unknown metal. 2 Al3+(
jasenka [17]

Answer:

magnesium metal

Explanation:

According to the redox reaction equation, six electrons were transferred hence n=6 and F= Faraday's constant 96500C. ∆G° is given hence E°cell can easily be calculated as follows:

From ∆G°= -nFE°cell

E°cell= -∆G°/nF= -(-411×10^3/96500×6)

E°cell= 0.7098V

But for Al3+(aq)/Al(s) half cell, E°= -1.66V from standard table of reduction potentials.

E°cell= E°cathode- E°anode but Al3+(aq)/Al(s) half cell is the cathode

Hence

E°anode=E°cathode - E°cell

E°anode= -1.66-0.7098= -2.37V

This is the reduction potential of Mg hence the anode material was magnesium metal

5 0
3 years ago
Why do gasses condense when cooled
Darya [45]
Gassed condense because molecules decrease inside
6 0
3 years ago
The km of an enzyme is 5. 0 mm. Calculate the substrate concentration when this enzyme operates at one‑quarter of its maximum ra
Makovka662 [10]

The substrate concentration of the enzyme operating at one‑quarter of its maximum rate is = 0.333.

Relationship between Km and substrate concentration is -

Km is the concentration of substrate.It allows the enzyme to achieve half Vmax. High Km enzyme requires a higher concentration of substrate to get Vmax. Since, Km is a constant. If the substrate concentration is increased, it has no effect on it.

An enzyme with a high Km has a low affinity for its substrate. The substrate concentration Km corresponds to the substrate concentration.

The substrate concentration at which the reaction rate of the enzyme-catalyzed reaction is half of the maximum reaction rate Vmax.

The equation is:

                <em>V₀ = </em><u><em>Vmax [S] </em></u>

<em>                          [S] + Km</em>

Here,

V₀ is initial rate,

Km is the dissociation constant between the substrate and the enzyme,

Vmax is the maximum rate, and

S is the concentration of substrate.

taking fraction of V₀ and Vmax :

<u><em>    V₀    </em></u><em> = </em><u><em>     [S</em></u><em>]</em><u><em>     </em></u><em>  </em>

<em>Vmax      [S] + Km</em>

<u><em>   </em></u><u>V₀   </u> =   <u>   0.5Km   </u>  = 0.333

Vmax       1.50 + Km

Therefore, the substrate concentration of this enzyme operating at one‑quarter of its maximum rate is = 0.333.

To learn more about substrate concentration,

brainly.com/question/18237939

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3 0
1 year ago
7 grams of oxygen gas is reacted with excess C4H8. How many grams of CO2 gas at STP are produced?
ladessa [460]
I think 14 are produced because if you go up by that you get it
4 0
3 years ago
If 5.65 grams of zinc metal react with 21.6 grams of silver nitrate, how many grams of silver metal can be formed and how many g
Igoryamba
The balanced chemical reaction is:

Zn + 2AgNO3 =  Zn(NO3)2 + 2Ag

To determine the amount of the reactant left, we have to determine which is the limiting and the excess reactant. We do as follows:

5.65 g Zn ( 1 mol / 65.38 g) = 0.09 mol Zn
21.6 g AgNO3 (1 mol / 169.87 g) = 0.13 mol AgNO3

The limiting reactant would be silver nitrate since it is consumed completely in the reaction. The excess reactant would be zinc. 

Excess Zinc = 0.09 mol Zn - (0.13 / 2) mol Zn = 0.025 mol Zn left
7 0
4 years ago
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