All categories

3 years ago

How many grams of Na2SO4 are theoretically produced when excess NaCl reacts with 400 grams of H2SO4

Chemistry

1 answer:

Gnom [1K]3 years ago

3 0

Answer:

335.35 grams

Explanation:

Convert grams of H2SO4 to moles and get 4.08 moles.

Using stoichiometry, the chemical equation tells us that for every mole of H2SO4, one mole of Na2SO4 is produced. This means that, theoretically, you should get 4.08 moles.

Convert moles to grams and get 335.34 g.

However, if you were to actually perform this reaction, you would get less than the theoretical value.

Hope this helps! <3

You might be interested in

If an ocean current is moving northward from Antarctica and up the coast of Africa, the climate of the coastal land would be....

Illusion [34]

Answer:

I would say a cooled

Explanation:

because yeah it's going to be cold when it travels from Antarctica but then it's going on towards Africa and yeah the water is going to get warmth but it's going to cool the land of Antarctica because it's so dry and hot and humid but the water is going to be more warmed because Antarctica the water is freezing so you're trying to ask the temperature of the water it'd be more warm if you're trying to ask kind of like the temperature of the land it would be cooled

8 0

3 years ago

an atom has an atomic number of 9 a mass number of 19 and an electron configuration of 2-6-1 explain why the number of electrons

sukhopar [10]

You can tell that the atom is in the excited state because:

- Electron configuration should follow the 2-8-8-2 rule, meaning that the inner shell should be filled before the next shell can start holding electrons.

- Instead of the atom's electron configuration being in the ground state at 2-8-8-1, electrons from the second shell have jumped to the third.

5 0

3 years ago

When paper turns yellow-brown upon exposure to sunlight, what type of change is likely taking place?

DaniilM [7]

Answer:

The Answer Is Chemical Change :)

5 0

3 years ago

Considering that the mantle is 44.8% oxygen and 21.5% silicon by mass, calculate the mole ratio of oxygen atoms to silicon atoms

horrorfan [7]

The mantle has a mass of around $4.278 X 10 ^2^4 kg$ that is around 68.4% of earth's mass.

So to calculate moles we need to first find out the mass of oxygen and silicon present in mantle. It is given that oxygen is 44.8% by mass in mantle and 21.5% by mass in mantle, therefore to calculate its mass, we need to use $\text{mass percentage }=\frac{\text{mole of solute}}{\text{mass of solution}}\times100$

Now, to calculate mass percentage of oxygen

$44.8 =\frac{x}{4.278X10^2^4kg}\times100$

$x= 191.65\times10^2^2kg$

Similarly the mass of silicon can be calculated

$21.5 =\frac{x}{4.278X10^2^4kg}\times100$

$x=91.977\times10^2^2kg$

Now, the moles of any substance is calculated by

$\text{moles}= \frac{\text{given mass}}{\text{molar mass}}$

$\text{moles of oxygen}= \frac{191.65\times10^2^2kg}{2.6566962\times10^-^2^6kg}$

where, mass of oxygen in kilograms is $2.6566962\times10^-^2^6kg$

So, $\text{moles of oxygen}=72.1384\times10^4^8\text{moles of O}$

Similarly $\text{moles of silicon}= \frac{91.977\times10^2^2kg}{4.663\times10^-^2^6kg}$

$\text{moles of silicon}=19.724\times10^4^8\text{moles of Si}$

Now, to calculate mole ratio we need to divide every moles to the lowest calculated mole that is the moles of Si and round it off to the nearest whole number.

$\text{mole ratio of oxygen}= \frac{72.138\times10^4^8kg}{19.724\times10^4^8kg}$