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3 years ago

What is the Complete Ionic Equation of Iorn(III) Chloride and Sodium Hydroxide?

Chemistry

1 answer:

kiruha [24]3 years ago

4 0

Answer:

The equation is based on Iron (III) not lorn(III)

Explanation:

FeCl₃(aq) + 3 NaOH(aq) ---> $Fe(OH)_{3(s)}$ + 3 NaCl(aq)

[ Balanced Molecular Equation ]

$Fe^{3+(aq)}$ + 3 $Cl^{-(aq)}$ + 3 $Na^{+(aq)}$ + 3 $OH^{-(aq)}$ ---> $Fe(OH)_{3(s)}$ + 3 $Na^{+(aq)}$ + 3 $Cl^{-(aq)}$

[ Balanced Full Ionic Equation ]

$Fe^{3+(aq)}$ + 3 $OH^{-(aq)}$ ---> $Fe(OH)_{3(s)}$ Fe(OH)3(s)

[ Balanced Net Ionic Equation ]

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Formula for Tricarbon heptabromide.

DiKsa [7]

I believe it would be Au^4Cl8

7 0

3 years ago

Calculate the number of atoms of sodium in a 4.5-gram sample

allochka39001 [22]

Answer:

1.18×10²³ atoms.

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms.

From the above concept, 1 mole of sodium also contains 6.02×10²³ atoms.

1 mole of sodium = 23 g.

Thus,

23 g of sodium contains 6.02×10²³ atoms.

Therefore, 4.5 g of sodium will contain = (4.5 × 6.02×10²³)/23 = 1.18×10²³ atoms.

From the above calculation,

4.5 g of sodium contains 1.18×10²³ atoms.

7 0

3 years ago

Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine. CCl4(g) + (1/2)O

madam [21]

The question is incomplete, here is the complete question:

Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine.

$CCl_4(g)+\frac{1}{2}O_2(g)\rightleftharpoons COCl_2(g)+Cl_2(g);K_c=4.4\times 10^9$ at 1,000 K

Calculate Kc for the reaction $2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)$

<u>Answer:</u> The value of $K_c'$ for the final reaction is $1.936\times 10^{19}$

<u>Explanation:</u>

The given chemical equations follows:

$CCl_4(g)+\frac{1}{2}O_2(g)\rightleftharpoons COCl_2(g)+Cl_2(g);K_c$

We need to calculate the equilibrium constant for the equation, which is:

$2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)$

As, the final reaction is the twice of the initial equation. So, the equilibrium constant for the final reaction will be the square of the initial equilibrium constant.

The value of equilibrium constant for net reaction is:

$K_c'=(K_c)^2$

We are given:

$K_c=4.4\times 10^9$

Putting values in above equation, we get:

$K_c'=(4.4\times 10^9)^2=1.936\times 10^{19}$

Hence, the value of $K_c'$ for the final reaction is $1.936\times 10^{19}$

3 0

3 years ago

It the mass of a material is 46 grams and the volume of the material is 8 cm ^3 What would the density of the material to be

Nat2105 [25]

5.75 Grams per cm^3

You do mass divided by volume

3 0

3 years ago

Rank the following compounds from highest boiling to lowest boiling. To rank items as equivalent, overlap them.

Olegator [25]

1-pentanol > 1-butanol > 1-chlorobutane > pentane

Explanation:

You my find in the attached picture the structures of the compounds, names and also the variation of their boiling points.

Alcohols have higher boiling points because they form hydrogen bonds between the molecules.

Learn more about:

boiling points in organic compounds

brainly.com/question/2153588

#learnwithBrainly

7 0

2 years ago