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nordsb [41]
3 years ago
5

Which of the following is NOT a part of Dalton's atomic theory?

Chemistry
2 answers:
Gekata [30.6K]3 years ago
7 0

D.) Atoms are always in motion

xz_007 [3.2K]3 years ago
6 0

atoms are always in motion. i took the test and got it correct

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Explain the components of Petroleum and their uses.
RideAnS [48]
<h2>answer:</h2>

Various Constituents of Petroleum and their Uses

Constituents of Petroleum

Kerosene

uses➪ Fuel for stoves, in lamps and as aviation fuel for jet aircrafts

Constituents of Petroleum

LPG

uses➪ Fuel for home and industry

Constituents of Petroleum

Lubricating oil

uses➪Used for Lubrication in machines and engines

Constituents of Petroleum

Paraffin wax

uses➪ Ointments, candles, vaseline etc.

8 0
3 years ago
Pls help i am in 8th grade k12
zheka24 [161]
It’s definitely persuade!
4 0
2 years ago
Tris base has a molecular weight of 121 g/mol. How many grams of tris base would you need to make 250ml of a 200mM SOLUTION
STatiana [176]

Answer:

6.05 g

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

From the question ,

M = 200mM

Since,

1 mM = 10⁻³ M

M = 200 * 10⁻³ M

V = 250 mL

Since,

1 mL = 10⁻³ L

V = 250 * 10⁻³ L

The moles can be calculated , by using the above relation,

M = n / V  

Putting the respective values ,

200 * 10⁻³ M = n / 250 * 10⁻³ L

n = 0.05 mol

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

m = 121 g/mol

n = 0.05 mol ( calculated above )

The mass of tri base can be calculated by using the above equation ,

n = w / m  

Putting the respective values ,

0.05 mol = w / 121 g/mol

w = 0.05 mol * 121 g/mol

w = 6.05 g

3 0
4 years ago
Read 2 more answers
Plz help!!! This is timed!!!
pogonyaev
58.7 %

Please correct me if I’m wrong. :)
7 0
2 years ago
The strongest intermolecular interactions between pentane (c5h12) molecules arise from
Andrew [12]
The intermolecular interactions found between pentane molecules are London-Dispersion Forces.

Explaination:

Step 1:
           Instantaneous Dipole: As the pentane molecule is non polar in nature and the electron density on each molecule is symmetrical. When this symmetrical molecule approaches second symmetrical molecule there disturbance is caused due to repulsion between electrons. Due to repulsion the electrons changes there position and for a small period of time an instantaneous dipole is produced on pentane molecule.

Step 2:
           Induced Dipole:
The dipole produced in step one when approaches another symmetrical pentane molecule, the partial positive part (low electron density site) attracts the electron from symmetrical pentane and induces polarity in it.

In this way the process repeats and interactions are developed between the non polar pentane molecules. 
7 0
3 years ago
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