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aksik [14]
3 years ago
11

-4zsquared +zsquared

Mathematics
1 answer:
TEA [102]3 years ago
5 0

-4

Step-by-step explanation:

-4z² + z²

let's assume you have z² and you're owing 4z², you'll pay the z² you have and you'll still owe 4

so that is -4

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Can I do 50 quizzes in 2 weeks? Each takes about 5 minutes
rodikova [14]
So.
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Let's get started with formulas.
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I KNOW you hate formulas!! So do I, but we have to use them. No "buts". 
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So, how many minutes are in 2 weeks?
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Search it up. For your convenience, it is 20,160 minutes.
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Well, I think you have your answer, since each quiz is 5 minutes, 5 times 50 (5 x 50) is 2,500 minutes.
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Yes, you can do 50 quizzes and MUCH MUCH more in 2 weeks.
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Hope I helped!!
8 0
3 years ago
Read 2 more answers
What is Limit of StartFraction StartRoot x + 1 EndRoot minus 2 Over x minus 3 EndFraction as x approaches 3?
scoray [572]

Answer:

<u />\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \boxed{ \frac{1}{4} }

General Formulas and Concepts:

<u>Calculus</u>

Limits

Limit Rule [Variable Direct Substitution]:
\displaystyle \lim_{x \to c} x = c

Special Limit Rule [L’Hopital’s Rule]:
\displaystyle \lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Addition/Subtraction]:
\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]
Derivative Rule [Basic Power Rule]:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given limit</em>.

\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3}

<u>Step 2: Find Limit</u>

Let's start out by <em>directly</em> evaluating the limit:

  1. [Limit] Apply Limit Rule [Variable Direct Substitution]:
    \displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \frac{\sqrt{3 + 1} - 2}{3 - 3}
  2. Evaluate:
    \displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \frac{\sqrt{3 + 1} - 2}{3 - 3} \\& = \frac{0}{0} \leftarrow \\\end{aligned}

When we do evaluate the limit directly, we end up with an indeterminant form. We can now use L' Hopital's Rule to simply the limit:

  1. [Limit] Apply Limit Rule [L' Hopital's Rule]:
    \displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\\end{aligned}
  2. [Limit] Differentiate [Derivative Rules and Properties]:
    \displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \leftarrow \\\end{aligned}
  3. [Limit] Apply Limit Rule [Variable Direct Substitution]:
    \displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \leftarrow \\\end{aligned}
  4. Evaluate:
    \displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \\& = \boxed{ \frac{1}{4} } \\\end{aligned}

∴ we have <em>evaluated</em> the given limit.

___

Learn more about limits: brainly.com/question/27807253

Learn more about Calculus: brainly.com/question/27805589

___

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

3 0
1 year ago
Help in dying please​
Mkey [24]

Answer:

hello! :) i hope your having a wonderful day :)

Step-by-step explanation:

7 0
3 years ago
If y = 3x+b intersects y= mx +3 at (2, 3), find the value of b and m.
Darina [25.2K]

Answer:

The value of b is -3 and m is 0.

Step-by-step explanation:

You have to substitute the coordinates into both equation in order to find m and b value :

Find m,

y = mx + 3

At (2,3),

3 = m(2) + 3

3 - 3 = 2m

2m = 0

m = 0

Find b,

y = 3x + b

At (2,3),

3 = 3(2) + b

b + 6 = 3

b = 3 - 6

b =  - 3

3 0
2 years ago
Read 2 more answers
Subtract.<br> 5x – 6x+2<br> - 1-2x - x - 2)
adell [148]

Answer:

7x^2 -5x + 4

Step-by-step explanation:

5x^2 – 6x+2

- (-2x^2 - x - 2)

We got 5x^2 - (-2x^2) = 5x^2 + 2x^2 = 7x^2

-6x - (-x) = -6x + x = -5x

2 - (-2) = 2+2 = 4

So the equation would be 7x^2 -5x + 4

Hope this help :3

3 0
3 years ago
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